Answer: m (CO) = n*M, where n is the amount of substance, mole, M is the molar mass, g/mole m (CO) = 4*28 = 112 g % C = m (C)*100% / m (CO) = 48*100 % / 112 = 42.8 %
You can calculate this by such reaction: NH₄NO₃ --gt; N₂ + frac12;O₂ + 2H₂O ==gt; 2NH₄NO₃ --gt; 2N₂ + O₂ + 4H₂O The law of conservation of mass solves this...
4NH3 + 7O2 = 4NO2 + 6H2OAccording to the equation NH3 reacts completely, O2 is in the excess.7 mol of NO2 will be produced.According to the equation 7mol*7/4 = 12....