1) How many moles of carbon monoxide would be required to react with 3.24 moles of iron (III) oxide? Fe<sub>2</sub>O<sub>3</sub>(s)+ 3 CO(g) 🡪 2 Fe(g) + 3 CO<sub>2</sub>(g)

Md Ariful Islam

0 like 0 dislike
1 views
Share with your friends

1 Answers

Md Ariful Islam

Call

Solution:

The balanced chemical equation:

Fe2O3(s) + 3CO(g) → 2Fe(g) + 3CO2(g)

According to the equation above: n(Fe2O3) = n(CO)/3

n(CO) = 3 × n(Fe2O3) = 3 × 3.24 mol = 9.72 mol

n(CO) = 9.72 mol

Answer: 9.72 moles of carbon monoxide (CO) would be required.

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
How many mL of 0.250 M KOH will react with 15.0 mL of 0.350 M H<sub>2</sub>SO<sub>4</sub>? The reaction is : 2KOH + H<sub>2</sub>SO<sub>4</sub> → K<sub>2</sub>SO<sub>4</sub> + 2H<sub>2</sub>O

mL of 0.250 M KOH=5.5

1 Answers 1 views
Consider the following balanced equation. 4 NH<sub>3</sub> + 5 O<sub>2</sub> 4 NO + 6 H<sub>2</sub>O How many moles of O<sub>2</sub> are required to react with 6.9 moles of NH<sub>3</sub>?

solution4NH3+5O2→4NO+2O  5 moles of oxygen required to react with a mole of ammoniaThus x mole of oxygen will react with (6.9/ 17) mole of ammoniax={(5×6.9)/ (4×17)} ​=0.5Hence, the number moles of O2​ required is 0.5 mol.

1 Answers 1 views
In the following reaction, how many liters of O<sub>2</sub> will produce 43.62 liters of CO<sub>2</sub> at STP? C<sub>3</sub>H<sub>8</sub> + 5 O<sub>2</sub> 3 CO<sub>2</sub> + 4 H<sub>2</sub>O

Litres of O2=72.7L O2

1 Answers 1 views
How many moles of CO<sub>2</sub> will be produced when you burn 12.5 moles of C<sub>2</sub>H<sub>4</sub>? ( C<sub>2</sub>H<sub>4</sub> + 3 O<sub>2</sub> ---&gt; 2 CO<sub>2</sub> + 2 H<sub>2</sub>O )

Mole ratio C2H4:CO2=1:2= 12.5×2=25moles of CO2

1 Answers 1 views
Can you please help me balance this equation?Na[sub]3[/sub]PO[sub]4[/sub] + Ba(NO[sub]3[/sub])[sub]2[/sub] = Ba[sub]3[/sub](PO[sub]4[/sub])[sub]2[/sub] + NaNO[sub]3[/sub]

The correct balanced equation is: Na3PO4 + Ba(NO3)2 = BaPO4 + Na3(NO3)2

1 Answers 1 views
Iron oxide formula Fe<sub>2</sub>O<sub>3 </sub>how many molecules of Fe<sub>3</sub>O<sub>3 </sub>there in (5x<sup>2</sup>) mol of Fe<sub>2</sub>O<sub>3</sub>, if x=4?

3.21 * 1025 molecules

1 Answers 1 views
How many moles of NO<sub>2</sub> would result from mixing 1.5 mole of N<sub>2</sub> with 2.5 moles of O<sub>2</sub>? N<sub>2</sub> + 2 O<sub>2</sub> ----&gt; 2 NO<sub>2</sub>

1.5 moles of N2 and 2.5 moles of O2 Then O2 is limiting Reagent .2 moles O2 gives 2 moles of NO2 .2.5 moles of O2 gives 2.5 moles of...

1 Answers 1 views
If you have 9.7 moles of O<sub>2</sub> how many moles of water could you make? C<sub>3</sub>H<sub>8</sub>+ 5O<sub>2</sub> → 3CO<sub>2</sub> + 4H<sub>2</sub>O

Solution:Balanced chemical equation:C3H8 + 5O2 → 3CO2 + 4H2OAccording to the equation above: n(O2)/5 = n(H2O)/4Thus,n(H2O) = 4 × n(O2) / 5 = (4 × 9.7 mol) / 5 = 7.76 moln(H2O) =...

1 Answers 1 views
How many moles of ammonium sulfate can be made from the reaction of 30.0 moles of ammonia and sulfuric acid? NH<sub>3 </sub>+ H<sub>2</sub>SO<sub>4</sub> → (NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub>

Solution:Balanced chemical equation:2NH3 + H2SO4 → (NH4)2SO4According to the equation above: n[NH3]/2 = n[(NH4)2SO4]Therefore,n[(NH4)2SO4] = n[NH3] / 2 = 30.0 mol / 2 = 15.0 mol (NH4)2SO4Answer: 15.0 moles of ammonium sulfate can...

1 Answers 1 views
(NH<sub>4</sub>)<sub>2</sub>CO<sub>3</sub> + H<sub>2</sub>SO<sub>4</sub> → (NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub> + CO<sub>2</sub> + H<sub>2</sub>O net ionic equation

2 NH4 + + CO3 -2+ 2H + +SO4 2-= 2 NH4 + +SO4 2-+ CO2+H2O2NH4++CO3−2+2H++SO42−=2NH4++SO42−+CO2+H2O

1 Answers 1 views
X