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Fe<sub>2</sub>O<sub>3</sub>+3CaS = Fe<sub>2</sub>S<sub>3</sub>+3CaO How many grams of Fe<sub>2</sub>O<sub>3</sub> are needed to produce 51.9 grams of CaO?
Solution:Fe2O3 + 3CaS = Fe2S3 + 3CaOx g 51,9 g(Fe2O3) = 56*2+16*3= 160g/mol(CaO)=40+16=56g/molXmol(CaO)= 51,9/56= 0,96Xmol(Fe2O3)=0,92/3=0,308Xg(Fe2O3)=160*0,308/1=49,28Answer:m(Fe2O3)=49,28g
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What is the ΔH° for the following reaction (in kJ/mol)? 2 Na <sub>(s) </sub>+ 2 H<sub>2</sub>O<sub> (l)</sub> →<sub> </sub> 2 NaOH<sub> (aq) </sub>+ H<sub>2</sub> <sub>(g)</sub>
From the given info, we know the amount of heat released when 2 moles of Na is reacted. We're asked for the heat per 0.5 moles. So, (368.6 kJ/2mol)0.5000 mol = 92.15...
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Consider the following balanced equation. 4 NH<sub>3</sub> + 5 O<sub>2</sub> 4 NO + 6 H<sub>2</sub>O How many moles of O<sub>2</sub> are required to react with 6.9 moles of NH<sub>3</sub>?
solution4NH3+5O2→4NO+2O 5 moles of oxygen required to react with a mole of ammoniaThus x mole of oxygen will react with (6.9/ 17) mole of ammoniax={(5×6.9)/ (4×17)} =0.5Hence, the number moles of O2 required is 0.5 mol.
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In the following reaction, how many liters of O<sub>2</sub> will produce 43.62 liters of CO<sub>2</sub> at STP? C<sub>3</sub>H<sub>8</sub> + 5 O<sub>2</sub> 3 CO<sub>2</sub> + 4 H<sub>2</sub>O
Litres of O2=72.7L O2
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How many moles of CO<sub>2</sub> will be produced when you burn 12.5 moles of C<sub>2</sub>H<sub>4</sub>? ( C<sub>2</sub>H<sub>4</sub> + 3 O<sub>2</sub> ---> 2 CO<sub>2</sub> + 2 H<sub>2</sub>O )
Mole ratio C2H4:CO2=1:2= 12.5×2=25moles of CO2
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Can you please help me balance this equation?Na[sub]3[/sub]PO[sub]4[/sub] + Ba(NO[sub]3[/sub])[sub]2[/sub] = Ba[sub]3[/sub](PO[sub]4[/sub])[sub]2[/sub] + NaNO[sub]3[/sub]
The correct balanced equation is: Na3PO4 + Ba(NO3)2 = BaPO4 + Na3(NO3)2
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Iron oxide formula Fe<sub>2</sub>O<sub>3 </sub>how many molecules of Fe<sub>3</sub>O<sub>3 </sub>there in (5x<sup>2</sup>) mol of Fe<sub>2</sub>O<sub>3</sub>, if x=4?
3.21 * 1025 molecules
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How many moles of NO<sub>2</sub> would result from mixing 1.5 mole of N<sub>2</sub> with 2.5 moles of O<sub>2</sub>? N<sub>2</sub> + 2 O<sub>2</sub> ----> 2 NO<sub>2</sub>
1.5 moles of N2 and 2.5 moles of O2 Then O2 is limiting Reagent .2 moles O2 gives 2 moles of NO2 .2.5 moles of O2 gives 2.5 moles of...
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If you have 9.7 moles of O<sub>2</sub> how many moles of water could you make? C<sub>3</sub>H<sub>8</sub>+ 5O<sub>2</sub> → 3CO<sub>2</sub> + 4H<sub>2</sub>O
Solution:Balanced chemical equation:C3H8 + 5O2 → 3CO2 + 4H2OAccording to the equation above: n(O2)/5 = n(H2O)/4Thus,n(H2O) = 4 × n(O2) / 5 = (4 × 9.7 mol) / 5 = 7.76 moln(H2O) =...
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How many moles of ammonium sulfate can be made from the reaction of 30.0 moles of ammonia and sulfuric acid? NH<sub>3 </sub>+ H<sub>2</sub>SO<sub>4</sub> → (NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub>
Solution:Balanced chemical equation:2NH3 + H2SO4 → (NH4)2SO4According to the equation above: n[NH3]/2 = n[(NH4)2SO4]Therefore,n[(NH4)2SO4] = n[NH3] / 2 = 30.0 mol / 2 = 15.0 mol (NH4)2SO4Answer: 15.0 moles of ammonium sulfate can...
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