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Fe<sub>2</sub>O<sub>3</sub>+3CaS = Fe<sub>2</sub>S<sub>3</sub>+3CaO How many grams of Fe<sub>2</sub>O<sub>3</sub> are needed to produce 51.9 grams of CaO?
Solution:Fe2O3 + 3CaS = Fe2S3 + 3CaOx g 51,9 g(Fe2O3) = 56*2+16*3= 160g/mol(CaO)=40+16=56g/molXmol(CaO)= 51,9/56= 0,96Xmol(Fe2O3)=0,92/3=0,308Xg(Fe2O3)=160*0,308/1=49,28Answer:m(Fe2O3)=49,28g
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What is the ΔH° for the following reaction (in kJ/mol)? 2 Na <sub>(s) </sub>+ 2 H<sub>2</sub>O<sub> (l)</sub> →<sub> </sub> 2 NaOH<sub> (aq) </sub>+ H<sub>2</sub> <sub>(g)</sub>
From the given info, we know the amount of heat released when 2 moles of Na is reacted. We're asked for the heat per 0.5 moles. So, (368.6 kJ/2mol)0.5000 mol = 92.15...
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How many mL of 0.250 M KOH will react with 15.0 mL of 0.350 M H<sub>2</sub>SO<sub>4</sub>? The reaction is : 2KOH + H<sub>2</sub>SO<sub>4</sub> → K<sub>2</sub>SO<sub>4</sub> + 2H<sub>2</sub>O
mL of 0.250 M KOH=5.5
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How many moles of CO<sub>2</sub> will be produced when you burn 12.5 moles of C<sub>2</sub>H<sub>4</sub>? ( C<sub>2</sub>H<sub>4</sub> + 3 O<sub>2</sub> ---> 2 CO<sub>2</sub> + 2 H<sub>2</sub>O )
Mole ratio C2H4:CO2=1:2= 12.5×2=25moles of CO2
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Can you please help me balance this equation?Na[sub]3[/sub]PO[sub]4[/sub] + Ba(NO[sub]3[/sub])[sub]2[/sub] = Ba[sub]3[/sub](PO[sub]4[/sub])[sub]2[/sub] + NaNO[sub]3[/sub]
The correct balanced equation is: Na3PO4 + Ba(NO3)2 = BaPO4 + Na3(NO3)2
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Iron oxide formula Fe<sub>2</sub>O<sub>3 </sub>how many molecules of Fe<sub>3</sub>O<sub>3 </sub>there in (5x<sup>2</sup>) mol of Fe<sub>2</sub>O<sub>3</sub>, if x=4?
3.21 * 1025 molecules
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How many moles of NO<sub>2</sub> would result from mixing 1.5 mole of N<sub>2</sub> with 2.5 moles of O<sub>2</sub>? N<sub>2</sub> + 2 O<sub>2</sub> ----> 2 NO<sub>2</sub>
1.5 moles of N2 and 2.5 moles of O2 Then O2 is limiting Reagent .2 moles O2 gives 2 moles of NO2 .2.5 moles of O2 gives 2.5 moles of...
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Using the following chemical equation how many liters of carbon dioxide can be produced by burning 79 L of oxygen? C<sub>4</sub>H<sub>10</sub> + 5O<sub>2</sub> -> 3CO<sub>2</sub> + 4H<sub>2</sub>O
C4H10 + 5O2 -> 3CO2 + 4H2O - unbalanced equationSolution:The balanced chemical equation:2C4H10 + 13O2 → 8CO2 + 10H2OAccording to the equation above: n(O2)/13 = n(CO2)/8At STP, one mole of any gas occupies a volume of 22.4 L (Vm).Hence,V(O2)...
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Using the following chemical equation how many liters of oxygen are consumed by burning 7.86 g of butane? C<sub>4</sub>H<sub>10</sub> + 5O<sub>2</sub> -> 3CO<sub>2</sub> + 4H<sub>2</sub>O
C4H10 + 5O2 → 3CO2 + 4H2O - unbalanced equationSolution:C4H10 - butaneThe balanced chemical equation:2C4H10 + 13O2 → 8CO2 + 10H2OAccording to the equation above: n(C4H10)/2 = n(O2)/13Moles of C4H10 = Mass of C4H10 / Molar mass of C4H10The molar mass of...
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How many moles of ammonium sulfate can be made from the reaction of 30.0 moles of ammonia and sulfuric acid? NH<sub>3 </sub>+ H<sub>2</sub>SO<sub>4</sub> → (NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub>
Solution:Balanced chemical equation:2NH3 + H2SO4 → (NH4)2SO4According to the equation above: n[NH3]/2 = n[(NH4)2SO4]Therefore,n[(NH4)2SO4] = n[NH3] / 2 = 30.0 mol / 2 = 15.0 mol (NH4)2SO4Answer: 15.0 moles of ammonium sulfate can...
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