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2CH<sub>3</sub>OH+3O<sub>2 </sub>= 2CO<sub>2</sub>+4H<sub>2</sub>O If 3 moles of methanol are used up in the combustion process, How many moles of H<sub>2</sub>O is produced?
In the above reaction 2 moles of methanol give 4 moles of water So according to that 1 moles of methanol gives 2 moles of water Now,3 moles of methanol...
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What is the ΔH° for the following reaction (in kJ/mol)? 2 Na <sub>(s) </sub>+ 2 H<sub>2</sub>O<sub> (l)</sub> →<sub> </sub> 2 NaOH<sub> (aq) </sub>+ H<sub>2</sub> <sub>(g)</sub>
From the given info, we know the amount of heat released when 2 moles of Na is reacted. We're asked for the heat per 0.5 moles. So, (368.6 kJ/2mol)0.5000 mol = 92.15...
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Based on this balanced equation: 2LiOH + H<sub>2</sub>S → Li<sub>2</sub>S + 2H<sub>2</sub>O How many moles of Li<sub>2</sub>S will be produced from 150.17 g of LiOH and excess H<sub>2</sub>S?
Molar Mass of LiOH = 23.95Molar Mass of H2S= 34.1Molar Mass of Li2S = 45.95From the equation, = 2/3 × 150.17 = 100.1133g of LiOH= 100.1133 /23.95 = 4.18moles of...
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How many mL of 0.250 M KOH will react with 15.0 mL of 0.350 M H<sub>2</sub>SO<sub>4</sub>? The reaction is : 2KOH + H<sub>2</sub>SO<sub>4</sub> → K<sub>2</sub>SO<sub>4</sub> + 2H<sub>2</sub>O
mL of 0.250 M KOH=5.5
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In the following reaction, how many liters of O<sub>2</sub> will produce 43.62 liters of CO<sub>2</sub> at STP? C<sub>3</sub>H<sub>8</sub> + 5 O<sub>2</sub> 3 CO<sub>2</sub> + 4 H<sub>2</sub>O
Litres of O2=72.7L O2
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Can you please help me balance this equation?Na[sub]3[/sub]PO[sub]4[/sub] + Ba(NO[sub]3[/sub])[sub]2[/sub] = Ba[sub]3[/sub](PO[sub]4[/sub])[sub]2[/sub] + NaNO[sub]3[/sub]
The correct balanced equation is: Na3PO4 + Ba(NO3)2 = BaPO4 + Na3(NO3)2
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How many moles of NO<sub>2</sub> would result from mixing 1.5 mole of N<sub>2</sub> with 2.5 moles of O<sub>2</sub>? N<sub>2</sub> + 2 O<sub>2</sub> ----> 2 NO<sub>2</sub>
1.5 moles of N2 and 2.5 moles of O2 Then O2 is limiting Reagent .2 moles O2 gives 2 moles of NO2 .2.5 moles of O2 gives 2.5 moles of...
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If you have 9.7 moles of O<sub>2</sub> how many moles of water could you make? C<sub>3</sub>H<sub>8</sub>+ 5O<sub>2</sub> → 3CO<sub>2</sub> + 4H<sub>2</sub>O
Solution:Balanced chemical equation:C3H8 + 5O2 → 3CO2 + 4H2OAccording to the equation above: n(O2)/5 = n(H2O)/4Thus,n(H2O) = 4 × n(O2) / 5 = (4 × 9.7 mol) / 5 = 7.76 moln(H2O) =...
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If 5 moles of N<sub>2 </sub>reacted with 12 moles of O<sub>2 </sub>according to 0 N2 + 2 O<sub>2 </sub>+ NO<sub>2 </sub>how many moles NO<sub>2 </sub>are produced
Solution:Balanced chemical equation:N2 + 2O2 → 2NO2According to the equation above: 2×n(N2) = n(O2) = n(NO2)Moles of each reactant:n(N2) = 5 moln(O2) = 12 molChoose one reactant and determine how many...
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How many moles of ammonium sulfate can be made from the reaction of 30.0 moles of ammonia and sulfuric acid? NH<sub>3 </sub>+ H<sub>2</sub>SO<sub>4</sub> → (NH<sub>4</sub>)<sub>2</sub>SO<sub>4</sub>
Solution:Balanced chemical equation:2NH3 + H2SO4 → (NH4)2SO4According to the equation above: n[NH3]/2 = n[(NH4)2SO4]Therefore,n[(NH4)2SO4] = n[NH3] / 2 = 30.0 mol / 2 = 15.0 mol (NH4)2SO4Answer: 15.0 moles of ammonium sulfate can...
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