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1. Calculate the [OH<sup>-</sup>] and pH of each of the following strong base solutions: a. 0.0050 M KOH b. 2.055 g of KOH in 500.0 mL of solution c. 1.00 mL of 0.175 M NaOH diluted to 2.00 L.
We are given 0.0050 M KOH solution:KOH is a strong base, so it dissociates in the solution 100% as follows:KOH→K++OH-The concentration of hydroxide ion is equal to the that of...
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for the reactions shown below-
a) CH4+2O2->CO2+2H20 caculate the amoun in grams of water generated when 10 grams of it is reacted with the correct amount of oxygen
10 m CH4 + 2O2 --gt; CO2 + 2H2O 16 2*18 m = 10*2*18/16 = 22.5 g
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2C2H6+7O2->4CO2+6H20
Caculate the volume of carbon dioxide produced when 2grams of it is reacted with the correct amount of oxygen
2 v 2C2H6 + 7O2 --gt; 4CO2 + 6H2O 2*30 4*22.4 v = 2*4*22.4/60 = 2.986 L
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C3H8+5O2->3CO2+4H2O
Caculate the amount in cubic meters of air ( 21% oxygen) required when 10 cubic feet of it is burned?
10 cubic feet = 283.168466 L volume is proportional to equivalents in equation C3H8 : O2 like 1:5 so, for burning we need 283.168466*5=1415.842 L 1415.842 L is 21% x-------------100%...
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A volume of 60.0 mL of a 0.160 M HNO3 solution is titrated with 0.360 M KOH. Calculate the volume of KOH required to reach the equivalence poi
V(KOH)·c(KOH) = V(HNO3)·c(HNO3) V(KOH) = V(HNO3)·c(HNO3)/c(KOH) = 60·0.16/0.36 = 26.7 (ml)
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Balanced equations for the following does reaction occur thank you
Fe + HCl
Cu + HCl
Zn + HCl
Fe + HNO3
Cu + HNO3
Zn + HNO3
Fe(s) + 2HCl(aq) → FeCl2(aq) + H2(g) – reaction occurs Cu(s) + 2HCl(g) → CuCl2(s) + H2(g) – reaction occurs at 600 Celcius Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g)...
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What would it look like and does a reaction occur:
Fe and HCl
Zn and HCl
Cu and HCl
Fe and HNO3
Cu and HNO3
Zn and HNO3
Iron and zinc force out hydrogen from hydrochloric acid: Fe + 2HCl → FeCl2 + H2↑ Zn + 2HCl → ZnCl2 + H2↑ Copper is among tension after hydrogen therefore...
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If instead of using HNO3, you used HCl with the same volume and concentration as HNO3, would you use the same volume of NaOH to reach the endpoint? What about using H2SO4?
1. NaOH + HCl = NaCl + H₂O 2. NаOH + HNO3 = NаNO3 + H2O 3. 2NaOH + H2SO4 = Na2SO4 + 2H2O In the first and second cases...
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How many grams of Ca(OH) 2 would be produced from the reaction of 25.0 grams of NaOH with 29.1 grams of CaCl 2 ? 2 NaOH(aq)+CaCl 2 (aq) Ca(OH) 2 (s)+2 NaCl(aq)
19,4 g
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Calculate the solution conductivities of 0.1 M KOH, 0.1 M NaOH and 0.1 M HNO3. Assume that they are fully dissociated
LKOH = lK+ + lOH- [L=molar conductivity, lK+ and lOH- molar ionic conductivity of K+ and OH- respectively] = 73.5+198.6 Sm2mol-1 = 272.1 Sm2mol-1L = (1000×K)/C K = conductivityConductivity of 0.1 M KOH is K...
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