a) Al:O= 4:3Al: Al2O3= 2:1O: Al2O3= 3:2b)Fe: H2O= 3:4Fe:Fe3O4= 3:1Fe: H2 = 3: 4
1 Answers 1 viewsIf 2Al2O3 --gt; 4Al+ 3O2; So, first of all we can find amount of substance of Al2O3: n(Al2O3) = m(Al2O3)/M(Al2O3); M(Al2O3) = Ar(Al)*2 + Ar(O) *3; M(Al2O3) = 27*2+16*3 =...
1 Answers 1 viewsAccording to the reaction, number of moles of KCl and O2 produced during the decomposition must be equal. As a result, the mass of oxygen equals:m(O2) = [m(KCl) × 3...
1 Answers 1 viewsSolution:The balanced chemical equation:4Al + 3O2 = 2Al2O3According to the chemical equation: n(Al)/4 = n(Al2O3)/2n(Al)/2 = n(Al2O3)n(Al) = 2 × n(Al2O3)Hence,n(Al) = 2 × 3.7 mol = 7.4 molMoles of...
1 Answers 1 viewsSolution:Balanced chemical equation:4Fe + 3O2 → 2Fe2O3According to stoichiometry: 4 mol of iron (Fe) produces 2 mol of iron(III) oxide (Fe2O3)Thus, 0.030 mol of iron (Fe) produces:(0.030 mol Fe) ×...
1 Answers 1 views2Al + Cr2O3 = Al2O3 +2 Сr1 mole of matter cntains 6.022×1023 elementary entities.1.20x1021 atoms of Al equals to 1.20x1021/ 6.022×1023 = 0.2x10-2 moles.According to the equation, n (Al2O3) =...
1 Answers 1 views4Li(s) + O2(g) → 2Li2O(s) 2Li (s) + 2H2O (l) → 2Li+(aq) + 2OH-(aq) + H2(g) Ca(s) + 2H2O(l) → Ca2+(aq) + 2OH-(aq) + H2(g) *Usually Ca(OH)2 is almost insoluble...
1 Answers 1 viewsSolution.n(KCl) = 77.8/74.5 = 1.044 mole = n(KClO3)1.044/2 = x/3 x = n(O2) = 1.566 molesm(O2) = 1.566 * 32 = 50.112 gAnswer. 50.112 g
1 Answers 1 viewsMass= Moles * Molecular weightMoles of KCl -> 62.3/74.5 = 0.84 molesMoles of KClO3=Moles of KCl (2KClO3⟶2KCl)Moles of KClO3=0.84 moles2KClO3⟶3O2 1 mole of KClO3 = 3/2 mole of O20.84 mole...
1 Answers 1 viewsAccording to the equation we obtain 3 molecules of H2O from each molecule of C2H5OH. Thus, from 0.100 mole of C2H5OH we will obtain 0.300 mole of H2O.
1 Answers 1 views