How many moles of oxygen are produced when 756 grams of lead 11 oxide are formed Find the mass of nitrogen dioxide that forms with 0.58 moles of oxygen

=207.2 amu (Pb)

Grams of aluminum oxide produced =12.57g

Lead (II) sulphate can be prepared by lead(II) oxide by warm sulphuric acid according to the following reaction: 23.6g xg PbO+H2SO4=PbSO4+H2O 1m 1m According to the stechiometric equation 1 mole...

Accordinng to the equation 3NO2(g) + H2O(l)------gt; NO(g) + 2HNO3(aq) we can find the amount of substance of water: n(NO2) : n(H2O) = 1:3; n(H2O) = n(NO2)*1/3 If the amount...

You can calculate this by such reaction: NH₄NO₃ --gt; N₂ + frac12;O₂ + 2H₂O ==gt; 2NH₄NO₃ --gt; 2N₂ + O₂ + 4H₂O The law of conservation of mass solves this...

Solution:The balanced chemical equation:2Mg + O2 → 2MgOAccording to the chemical equation: n(Mg)/2 = n(O2) = n(MgO)/2Molar mass of Mg is 24 g/mol.Moles of Mg = 10.8 g × (1...

CaCO3 = CaO + CO2 nCO2 = nCaCO3 = mCaCO3/MWCaCO3 = 10.5 g/100.0869 g/mol = 0.1049 mol; VCO2 = nCO2*Vm = 0.1049 mol*24 L/mol = 2.5178 L ≈ 2.52 L

1 . ᵽ = m/V, m = ᵽ * V m = 7*11,3 = 79,1g 2 . N = m/ma = 79,1/34*10⁻²² = 23,265*10²²

Firstly, we need to check if there is one of the reagents (O2 or Fe) in excess (it means that some amount either of O2 or Fe might be not...

CH4(g) + 2 O2 (g) = CO2(g) + 2 H2O (g)1 : 2 : 1 : 223g : 42g : ? : 37g Therefore : ( 23/42) =0.5 moles 1...