Answered Apr 23, 2024
5O2 + 4NH3 = 6H2O + 4NO5O2 = 6H2O5 × 32g O2 = 6 × 18g H2O1g O2 = 6×18/(5×32)g H2O2.1g O2 = 6×18×2.1/(5×32) g H2O= 1.42g H2O
Percent Yield =44.47%
It means that parallel with the main reaction occurring side reactions Main reaction: O* + *O = O2 Side reaction: 2*O + 2O2 = 2O3
Fe2O3(s) + 3C (s) --> 2Fe (s) + 3CO (s) The mass of CO produced in the reaction can be calculated using th following equation:m(CO) = [m(C) × 3 × Mr(CO)]...
Fe2O3M = 159,692Fe2M = 2*55.85 = 111.17 m (Fe) = 111.17*6.00/159,69 = 4,197 g - produced!
XO2 is 100 % and X is 80,so 2O is 20 % 2 atoms of Oxygen has molecular weight 16+16=32 (and it is 20 %) Now you can find molecular...
Mn(IO3)2 = 405 g/mol.x 0.266 = 107.73 g H2O= 18 g/mol x 0.734 = 13.212 g.107.73+13.212 = 120.942 g.V= 120.942/1.48 = 81.72 ml / 1000 = 0.08172 L.Cm= n/V =...
0.2 g
86.6/201:13.4/32=1:1.PbS.Pb+S=PbS.(10.5/201) x 32= 1.67164179 g of S
pV=nRT. n=pV/RT = 695 x 4500 / 62400 x 708= 0,0707912321 moles.0,0707912321 x 17 = 1,20345095 g.
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