6.023×1023 molecules of ammonia = 1 mole ammonia7.81×1024 molecules of ammonia = (1×7.81×1024) / 6.023×1023 = 12.9612.96 moles of ammonia was produced.
1 Answers 1 viewsMass of nitric oxide =14.4g
1 Answers 1 viewsc. NH3, NH4+, OH-
1 Answers 1 viewsVolume of reactants is proportional to coefficient in equation. So for this reaction we need correlation of volumes NH3 : O2 like 4:5 and we have 60:50,so NH3 is in...
1 Answers 1 viewsTherelative rate of diffusion will be sqrt (M(NH3)/M(NO)) = sqrt (17/30) = 0.753
1 Answers 1 viewsSolution:The molar mass of NH3 is 17.031 g/mol.Hence,a) Mole to Grams conversion:2.4 mol NH3 × (17.031 g NH3 / 1 mol NH3) = 40.8744 g NH3 = 40.87 g NH3Answer...
1 Answers 1 viewsdensity D = m / VV = m / DV (HNO3) = 10 / 1.11 = 9 ml
1 Answers 1 viewsSolution: ν(H2)=10.4/2=5.2 mol 3 mol H2→2 mol NH3, so ν(NH3)=(5.2/3)*2=3.47 mol m(NH3)=17*3.47-=58.99 g Answer: 58.99 grams of NH3.
1 Answers 1 viewsAnswer: 4 NH3 + 5O2 →4 NO +6 H2O From the reaction we can see that from 4 moles of ammonium we get 6 moles of water. M(NH3) =17 g/mol;...
1 Answers 1 views3,144 gr 6,348 gr xMn + yO =˃ MnxOy 55x 55x +16y 3,144×(55x+16y)=6,348 × 55x 172,92 x + 50,304y = 349,14x 50,304y=176,22x y=3,5x x=2 y=7 Answer: Mn2O7
1 Answers 1 views