If 7.0 moles of nh3 reacts with 14 moles of o2, how many moles of no2 will be produced? Calculate how many moles of excess reactant will remain

Md Ariful Islam

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4NH3 + 7O2 = 4NO2 + 6H2O

According to the equation NH3 reacts completely, O2 is in the excess.

7 mol of NO2 will be produced.

According to the equation 7mol*7/4 = 12. 25 mol of O2 reacts.

14 - 12.25 = 1.75 mol of O2 will remain.

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