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hexane-2 4-dione is right nomenclature but i want to know that why 2,4-diketo hexane is not used ?
The carbonyl groups, in this case keto groups are considered as functional groups and should be denoted by secondary suffix, one, whenever there are no other functional groups with higher...
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Show how you would accomplish the following conversions.
1.cis-hex-3-ene to (d,l)-hexane-3,4-diol
2.trans-hex-3-ene to meso-hexane-3,4-diol 3.trans-hex-3-ene to (d,l)-hexane-3,4-diol
1..cis-hex-3-ene to (d,l)-hexane-3,4-diolFor Above Conversion We Use " KMnO4( aq) / LOW Temperature ." 2..trans-hex-3-ene to meso-hexane-3,4-diolFor Above Conversion We Use " KMnO4( aq) / LOW Temperature ." 3..trans-hex-3-ene to...
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If one mole of any substance contains 6.022 x 1023 particles, does one mole of monoatomic oxygen (O) contain the same number of atoms as one mole of diatomic oxygen (O2)?
one mole of diatomic oxygen (O2) = 5.0234 mol
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during combustion of butane at 225 degrees celsius a mixture of 5.00dm of butane and 75.0 dm of oxygen was ignite ,is there enough oxygen for the complete combustion?
5.00 dm3 x1 x2 2C4H10(g) + 13O2(g) rarr; 8CO2(g) + 10H2O(l) 2 13 8 Volume of O2 x1=5*13/2=32.5 Volume of CO2 x2=5*8/2=20 1.Yes ,we need 32.5 and we have 75
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the combustion of N subscript 2 can result in 2 products: NO(g) or NO(g). Write a complete and balanced combustion reaction for one mole of N subscript 2 for each of the possible products.
N2+O2=2NO; N2+2O2=2NO2
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A fuel contains 4% hydrogen; 89% carbon; 1% sulphur; 2,5% oxygen, 3,5% ash and 20% excess air is supplies
Calculate
1.1 The mass of oxygen required to complete combustion of 1kg of fuel
1 kg of fuel contain 40 g of hydrogen, 890 g of carbon and 10 g of sulphur. 2H2 + O2 = 2H2O For complete combustion of 40 g of...
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P4 (s) + 5O2 (g) P4O10 (g)
a) What mass of P4O10 forms when 2.7 g of O2 is used?
Step 2: Mass to moles
Step 3: Mole to Mole (Ratio)
Step 4: Mole to Mass
P4 (s) + 5 O2 (g) = P4O10 (g)M (O2) = 32 g/molM (P4O10) = 283.9 g/moln (O2) = 2.7 / 32 = 0.08 moln (P4O10) = 1/5 x n...
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Gas barbecues burn propane using oxygen from the air. If 5.00 L of propane is burned, predict the volume of oxygen, at the same temperature and pressure, required for complete combustion.
Solution:Propane (C3H8).The balanced chemical equation:C3H8 + 5O2 = 3CO2 + 4H2OAccording to the equation: n(C3H8) = n(O2)/5n(gas) = V(gas) / VmHence,V(C3H8)/Vm = V(O2)/5VmV(C3H8) = V(O2)/5V(O2) = 5 × V(C3H8) =...
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when 1 mole of potassium carbonate reacts with 2 mole HCI, 1 mole carbon dioxide and 1 mole water is formed. How many mole potassium chloride is produced?
K2CO3 + 2 HCl = 2 KCl + H2О + CO2According to the balanced equation, in the given conditions 2 moles of potassium chloride will be forned.
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How many moles of water would be produced by the complete combustion of one mole of benzene, C6H6, in excess oxygen?
2C6H6 + 15O2 = 12CO2 + 6H2On(H2O) = (1*6)/2 = 3 moles
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