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The heat capacity of aluminum is 0.900 J/g degrees Celsius . How much energy is needed to raise the temperature of a 8.50 x 10^2 g block of aluminum from 22.8 degrees Celsius to 94.6 degrees Celsius
E = m*c*(t2 - t1) = 8.5*10^2*0.9*(94.6 - 22.8) = 54927 J
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how many ml of water at 10 degrees celsius (2 significant figures) must be added to 75 ml of water at 35 degrees celsius to obtain a final temperature of 19 degrees celsius?
Q=mCΔT ; where m is the mass of the substance, C is the specific heat of the substance, and ΔT is the difference in temperature.35 -19 = 1619-10 = 916...
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A sample of oxygen occupies a volume of 45ml at 91 Degrees Celsius. What will be the volume of oxygen when temperature drops at 10 Degrees Celsius
V1/T1 = V2/T245/364 = V2/283V2= 34.99ml
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calculate the mass of chlorine gas contained in a 5.00dm^3 flask at 25°C and 98 kPa pressure
According to ideal gas law: m/M×RT=PV Find the mass: m = (M×P×V)/(R×T) V = 0.005 m3 T = 298 K P = 98000 Pa R = 8.314 J×mol-1×K-1 M =...
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1)Prepare n-butanyl bromide from n-butane
2)Prepare Ethyl bromide from n-butane
3)Prepare 1-Butanol from n-butane
4)Prepare 2-Butene from n-butane
1) CH3-CH2-CH2-CH3 + Cl2 ---gt; CH3-CH2-CH2-CH2-Cl + HCl CH3-CH2-CH2-CH2-Cl + KOH (dry) --gt; CH3-CH2-CH2=CH2 CH3-CH2-CH2=CH2 + Br2/H2O2 --gt; CH3-CH2-CH2-CH2-Br CH3-CH2-CH2-CH2-Br + KOH (aq) --gt; CH3-CH2-CH2-CH2-OH + KBr CH3-CH2-CH2-CH2-OH + NaBr/H2SO4...
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Determine the new volume of a gas at that occpies an original volume of 55 L at 750mmHg and 25 degrees celsius if the pressure is changed to 1.03 atm and the temperature to 30 degrees celsius.
According to the ideal gas equation:P1V1/T1 = P2V2/T2,where P1, V1, T2 - initial pressure, volume and temperature, P2, V2, T2 - pressure, volume and temperatureAs a result:V2 = P1V1T2 /...
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A sample of an ideal gas has a volume of 3.60 L at 13.40 degrees Celsius and 1.30 atm. What is the volume of gas at 24.60 degrees Celsius and 0.990 atm
Combined gas Law P1V1 / T1 = P2V2 / T2 P1 = 1.30 atm V1 = 3.60 L T1 (must be in Kelvin = 13.40 deg C + 273.15) =...
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Explain how you would separate mixture of nitrogen and oxygen gases given that their boiling point are _196 degree Celsius and 183 degrees Celsius respectively
There are several ways of separating nitrogen and oxygen. The first involves cooling the mixture down to -200 degrees Celsius and separating the gases using a process called fractional distillation....
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If a gas is at 1.2atm, 25 degrees Celsius, and 10 liters what is the new volume if the pressure is changed to 2.8atm and the temperature to 35 degrees Celsius?
4.43 litersThe general gas equation :P1V1/T1 = P2V2/T2. Where p1=1.2atm; V1= 10 litersT1= 273 + 25=298 KP2=2.8 atmT2= 273+35=308 KV2 - ?V2=(p1*V1*T2)/(T1*p2) ;V2= 4,43 liters
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A helium balloon occupies 112mL at 90.0 kPa and 34 degrees Celsius. What volume would it occupy at standard temperature and pressure (101.3 kPa 0.00 degrees Celsius)
Use the combined gas law.P1V1/T1 = P2V2/T290*0.112/307 = 101.3*V2/2730.0328 = 0.3711*V2V2 = 0.088L
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