E = m*c*(t2 - t1) = 8.5*10^2*0.9*(94.6 - 22.8) = 54927 J
1 Answers 1 viewsV1/T1 = V2/T245/364 = V2/283V2= 34.99ml
1 Answers 1 viewsLet us denote mc - mass of copper = 35 g cc - specific heat capacity of copper = 385 J/(kg*K) tc - temperature of copper = 350 C =...
1 Answers 1 viewsFirst, let us assume that all added ice will be melted. Thus, the heat balance will follow the equation: m_i c_i ∆t_1+δ_i m_i+m_i c_w ∆t_2=m_w c_w ∆t_3 m_i-mass of ice,m_w-mass...
1 Answers 1 viewsAccording to the ideal gas equation:P1V1/T1 = P2V2/T2,where P1, V1, T2 - initial pressure, volume and temperature, P2, V2, T2 - pressure, volume and temperatureAs a result:V2 = P1V1T2 /...
1 Answers 1 viewsSolubility here is the amount of solute that is needed in order to reach saturated solution. If temperature remains constant then amount of solute is proportional to the amount of...
1 Answers 1 viewsSolution Nitric acid is a strong electrolyte and dissociates completely in solution: HNO 3 = H + + NO 3 - Calculate the number of moles of nitric acid: n(HNO...
1 Answers 1 viewsYou can determine how many grams of KNO3 can be dissolved in 100 g of water at 30°C by taking a look at its solubility graph. At 30°C KNO3 has...
1 Answers 1 viewsQ=c*m*(t2-t1); c=Q/[m*(t2-t1)]=133 cal/[0.25 kg*(40.1-23.0)C]=31.1 cal/(kg*C)
1 Answers 1 views4.43 litersThe general gas equation :P1V1/T1 = P2V2/T2. Where p1=1.2atm; V1= 10 litersT1= 273 + 25=298 KP2=2.8 atmT2= 273+35=308 KV2 - ?V2=(p1*V1*T2)/(T1*p2) ;V2= 4,43 liters
1 Answers 1 views