Heat=(m)(c)(change in T)Heat=(10)(0.9)(55-22)Heat =297J endothermic
1 Answers 1 viewsQ=mc∆T= 835.5 x 0.444 x 39 = 14 458,86 J.
1 Answers 1 viewsQ=mc∆T = 2.25 x 56 x 0.444 x (39.5-26.8) = 710,4888 J.
1 Answers 1 viewsIncrease in temperature = 232-10 = 222°CQ = Mc∆T= 140 × 0.9 × 22227972J= 27.972 kJ
1 Answers 1 viewsIncrease in temperature = 232-10 = 222°CQ = Mc∆T= 140 × 0.9 × 22227972J= 27.972 kJ
1 Answers 1 viewsQ=mCΔT ; where m is the mass of the substance, C is the specific heat of the substance, and ΔT is the difference in temperature.35 -19 = 1619-10 = 916...
1 Answers 1 views375oF =(375-32)*(5/9)oC=190.5oCIncrease in temperature =190.5-23=167.5Required Heat= 0.902*167.5*473 J=71463.205 J
1 Answers 1 viewsHeat( in joules) needed=209.346Joules
1 Answers 1 viewsHeat capacity or thermal capacity is a physical property of matter, defined as the amount of heat to be supplied to a given mass of a material to produce a...
1 Answers 1 viewsq = m x C xΔT q = 250g x 4.18J/goC x (98 – 22)oC q = 79.4 kJ
1 Answers 1 views