Determine the new volume of a gas at that occpies an original volume of 55 L at 750mmHg and 25 degrees celsius if the pressure is changed to 1.03 atm and the temperature to 30 degrees celsius.

Md Ariful Islam

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Md Ariful Islam

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According to the ideal gas equation:

P1V1/T1 = P2V2/T2,

where P1, V1, T2 - initial pressure, volume and temperature, P2, V2, T2 - pressure, volume and temperature

As a result:

V2 = P1V1T2 / T1P2.

Here,

P1 = 750 mmHg = 0.98684 atm, V1 = 55 L, T2 = 30°C = 303.15 K, T1 = 25°C = 298.15 K, P2 = 1.03 atm.

As a result, the new volume of the gas is:

V2 = 0.98684 atm × 55 L × 303.15 K / 298.15 K × 1.03 atm = 53.58 L.

Answer: 53.58 L

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