If a gas is at 1.2atm, 25 degrees Celsius, and 10 liters what is the new volume if the pressure is changed to 2.8atm and the temperature to 35 degrees Celsius?

Q=mCΔT ; where m is the mass of the substance, C is the specific heat of the substance, and ΔT is the difference in temperature.35 -19 = 1619-10 = 916...

0.918/22.7=0.04mol= 13.2/0.04=330g

From the Boyle–Mariotte law: P1V1 = P2V2V2 = P1×V1/V2V2 = 2,2×38/6,1 = 13,7 ml

According to the ideal gas equation:P1V1/T1 = P2V2/T2,where P1, V1, T2 - initial pressure, volume and temperature, P2, V2, T2 - pressure, volume and temperatureAs a result:V2 = P1V1T2 /...

P = 2 atmV = unknownn = 2.0 molR = 0.082 atm dm3 K-1 mol-1T = -133°C = 140 КSolution:The Ideal Gas equation can be used: PV = nRTTo find...

Combined gas Law P1V1 / T1 = P2V2 / T2 P1 = 1.30 atm V1 = 3.60 L T1 (must be in Kelvin = 13.40 deg C + 273.15) =...

PV = nRTV = nRT / P = (2 × 0.082 × (273.15 - 13)) / 2 = 21.33 dm3

P1*V1/T1 = P2*V2/T2V2 = T2*V1/T1 = 285K*0.0184L/297K = 0.01766 L

57.29kpa

Answer.Let the final temperature be T KAccording to ideal gas equation,(P1 x V1)/T1 = (P2 x V2)/T2At STP, P1 = 1atm, V1 = 10l, T1 =273KP2 = 2atm, V2 =...