100 mL = 0.1 LInitial amount in moles:1mol/L * 0.1L = 0.1 molFinal amount in moles:0.8mol/L * 0.1L = 0.08 molTherefore, the amount of sucrose adsorbed is 0.1 - 0.08...
deltaT = Kbmwhere: deltaT is the change in the boiling point of the solvent, Kb is the molal boiling point elevation constant (for water Kb=0.512oC⋅m-1) m is the molal concentration of the solute...
∆T=Kb×m, where m is molality (number of moles of solute per kilogramme of solvent).If the density of water is 1g/ml, 600 ml weights 600 g or 0.6 kg.Molality equals tom=1.55/0.6=2.58(mol/kg)∆T=T-T0,...
[Psaturated(water)-P(water)]/Psaturated(water)=1-xwater=xsugar, x is the mole fraction1 molal solution => 1 mol of sugar and 1 kg of water => 1 mol of sugar and 1000/18.015=55.402 mol of water => xsugar...
1 Answers
1 views
Log in to ask questions, provide answers, or leave comments.