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Calculate the mole fraction of 5.65g Calcium Chloride with molar mass of 111g/mole placed in 15.5g of H2O with molar mass of 18.0g/mole.
n(CaCl2) = (5.65 g)/(111 g/mol) = 0.051 moln(H2O) = (15.5 g)/(18 g/mol) = 0.861 molx(CaCl2) = 0.051/(0.051 + 0.861) = 0.0559 = 5.59%
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a solution contains 7.0 nonvolatile nonelectrolyte solute in 700g acetic acid at 150c determine the mm of the solute
61.8g/mol of the solute
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What is the boiling point elevation of a nonelectrolyte that is dissolved into a bottle of water to make a concentration of 1.86 m?
The boiling point is 101.53 °C
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10.0 g sample of an unknown compound is dissolved in 250 grams of benzene. The boiling point is raised 3.67*C above the boiling point of pre benzene. What is the molar mass of the sample?
Molar Mass of the sample ;=154.27g
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<ol><li> A solution is made by dissolving 125 g Na2SO4 in 65.0 g water. Calculate the mole fraction of the solute and the solvent. (MM Na2SO4 = 142 g/mole; water = 18 g/mole)</li></ol>
2NaOH+H2SO4→Na2SO4+2H2O= 65/18 = 3.61moles125/142 = 0.88MTotal moles = 4.91H2O = 3.61/4.91 = 0.74Na2SO4 = 0.88/4.91= 0.179
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To make a solution, 40 g of a nonelectrolyte is dissolved into 300 g of water. The freezing point depression of the solution is measured to be -7°C. Calculate the molar mass of the solute.
46.03g/mol
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A solution of 100.8 g of a non- dissociating solute in 135.0 g of water has a freezing point of -5.16 °C. What is the molar mass of the solute? Freezing point of water= 0 °C K-1.86 °C/m
Molar Mass of the solute=4.55M
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A solution containing 6.35 g nonelectrolyte dissolved in 500g of water freezes at -0.465°C. Determine the molecular weight of the solute.
The depression in the freezing point ΔKf = 0−(−0.465) = 0.465ΔTf=Kf x m0.465=1.86 mm = 0.25 mol/kgLet M be the molecular weight of solute.The number of moles is the ratio of...
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when 1 mole of potassium carbonate reacts with 2 mole HCI, 1 mole carbon dioxide and 1 mole water is formed. How many mole potassium chloride is produced?
K2CO3 + 2 HCl = 2 KCl + H2О + CO2According to the balanced equation, in the given conditions 2 moles of potassium chloride will be forned.
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What is the boiling point of a 0.66 molal solution of sucrose (nonelectrolyte) in ethanol? (Kb of ethanol = 1.22 °C/m, normal boiling point of ethanol is 78.5 °C)
∆Tb=Kb*Cm=1.22*0.66=0.81 °C;Tb(solution)=78.5 - ∆Tb=77.69 °C;Answer: 77.69°C
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