<ol><li> A solution is made by dissolving 125 g Na2SO4 in 65.0 g water. Calculate the mole fraction of the solute and the solvent. (MM Na2SO4 = 142 g/mole; water = 18 g/mole)</li></ol>

Molar mass of solvent = 42/ 0.6268= 66.8789Total mass= 66.8789 + 42= 108.8789Mass fraction= 42/108.8789= 0.3857Volume fraction = 0.3857/ 0.7304=0.528

0.8629×0.4040= 0.34860.3486/59= 0.006g=6/1000g

=35.3molal

2NaOH+H2​SO4​→Na2​SO4​+2H2​O= 65/18 = 3.61moles125/142 = 0.88MTotal moles = 4.91H2O = 3.61/4.91= 0.74Na2SO4 = 0.88/4.91= 0.179

Volume percent =45.7mL

The solute is non-volatile, so the vapor pressure will be equal to the pressure of the solvent. According to Raoult's law: Pi = xiPoi where xi is a mole fraction,...

 solute and solvent in a solution when contain equal amount of solute and solvent .then Both Have Equal Mass .let mass of solute and solvent both have " W "...

For the Na2SO4 solution m/v is (63g/260mL)*100%= 24.23% . For a carbonated drink m/v is (38/360)*100% =10.55%

In chemistry, a solution is a homogeneous mixture composed of two or more substances. In such a mixture, a solute is a substance dissolved in another substance, known as a...

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