Calculate the mass/volume percent, % (m/v) for the solute in each of the following solutions. 63g of Na2SO4 in 260mL of Na2SO4 solution 38g of sucrose in 360mL of a carbonated drink

С (molality of sucrose) = n (sucrose)/m (water);n (sucrose) = m/M = 67.9/342.2 = 0.2 mole;С (molality of sucrose) = 0.2 mole/94.9 = 0.0021 mole/kg.Answer: C = 0.0021 mole/kg.

2NaOH+H2​SO4​→Na2​SO4​+2H2​O= 65/18 = 3.61moles125/142 = 0.88MTotal moles = 4.91H2O = 3.61/4.91 = 0.74Na2SO4 = 0.88/4.91= 0.179

Ml of 10% Sucrose solution=83.3 ml

=35.3molal

Molar mass of Na2SO4= 142.04 g/mol95.5/142.04= 0.6720.672mol/1.15kg= 0.585mol/Kg

m = n*M, m - weight, n - quantity of substance, M - molecular weight mx /18 = mH2O / 82nx = nH2O / 9nx *Mx = nH2O * MH2O*18/82Mx...

Solution:The balanced chemical equation:2Al + 2NaOH + 2H2O → 2NaAlO2 + 3H2According to the equation above: n(Al) = n(NaOH)Moles of NaOH = 0.037 mol15.38 g Al × (1 mol Al /...

n = 4.63/342 = 0.0135 molesC = 0.0135/0.0168 = 0.8MAnswer. 0.8M

9,5238

m(C12H22O11) = 342.3 × 0.17 = 58.2 g C = 58.2 / 0.355 = 164 g/LMountain Dew