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Calculate the molality of a sucrose solution made by dissolving 67.9 grams sucrose into 94.9 grams water. The molar mass of sucrose is 342.2 g/mol.
С (molality of sucrose) = n (sucrose)/m (water);n (sucrose) = m/M = 67.9/342.2 = 0.2 mole;С (molality of sucrose) = 0.2 mole/94.9 = 0.0021 mole/kg.Answer: C = 0.0021 mole/kg.
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WHAT IS THE MOLARITY OF A SOLUTION MADE BY DISSOLVING 2.51GRAMS OF SODIUM CARBONATE IN DISTILLED WATER AND MAKING IT UP TO 100ML WITH DISTILLED WATER IN A VOLUMETRIC FLASK
Moles =mass ÷molar massMass =2.51gMolar mass =106Moles = 0.0156875
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A 4.85 g sample of anhydrous sodium sulfate is dissolved in water and the solution made up to 250 cm3 in a volumetric flask.
What is the concentration in mol dm−3 of sodium sulfate in the solution?
Concentration= amount of solute/volume im dm3Solution in dm3 = 250/1000 =0.25dm3now concentration in g/dm3=4.85/0.25 =19.4g/dm3Molecular mass of sodium sulfate is 142.04Now concentration in mol/dm3 becomes,19.4/142.04=0.13mol/dm3
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A sample solution containing sulfate ions (SO42−) was analyzed and was found to contain 5 mol of sulfate ions (SO42−).
Calculate the equivalent of sulfate ions (SO42−) present in the solution.
Answer on Question #83431, Chemistry/ Organic ChemistryA sample solution containing sulfate ions (SO42−) was analyzed and was found to contain 5 mol of sulfate ions (SO42−).Calculate the equivalent of sulfate...
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A 6.0 grams of NaOH is dissolved in distilled water to make 1.60 - liters of solution. What is the pH of the NaOH solution? AW Na = 23 g/mol ; AW O = 16 g/mol ; AW H = 1 g/mol
pH of the NaOH solution =12.7
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1. Determine the molarity of a solution containing 10.6g of sodium carbonate dissolve in
a)250cm³ of distilled water
b)500cm³ of distilled water
Solution:Molarity or molar concentration is the number of moles of solute per liter of solution, which can be calculated using the following equation:Molarity = mol solute / L of solution.Molar mass of sodium...
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2NaOH+H2SO4 - 2H2O+Na2SO4
how many grams of sodium sulfate will be formed if you start with 250 grams of sodium hydroxide and you have an excess of sulfuric acid?
First we must calculate the mole for NaOH. n(NaOH)=250/40= 6.25 moles of NaOH. From reaction we see than 2 moles of NaOH give 1 mole of Na2SO4. That means, that...
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A sample solution containing sulfate ions (SO42−) was analyzed and was found to contain 3 mol of sulfate ions (SO42−).
Calculate the equivalent of sulfate ions (SO42−) present in the solution.
Е=n·М/z=3·96/2=144g
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What is the molarity of a solution made by dissolving 2.00 g of sodium carbonate in distilled water and making it up to 250 mL with distilled water in a volumetric flask?
250 ml=0,25 LC=n/V;n=m/M;n(Na2CO3)=2/106=0,02 molC(Na2CO3)=0,02/0,25=0,08 mol/L
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A 48.00 mL solution of sodium sulfate has 11.46 * 10^23 atoms of sodium. What is concentration of the sodium sulfate solution in % by mass? (Assume the density of the solution is 1.04 g mL^-1)
Question is wrong! If calculate according to theory andwer will be 270%
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