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How many ml of 10% Sucrose solution should be added to 35 ml of 40% Sucrose solution to make a 15% Sucrose solution?
Ml of 10% Sucrose solution=83.3 ml
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A 95.5 grams of sodium sulfate (Na₂SO₄)is dissolved in 1150 grams of distilled H2O. Calculate the molality of the Na₂SO₄ solution. Molar mass: Na = 23 g/mol ; S = 32 g/mol ; O = 16 g/mol
Molar mass of Na2SO4= 142.04 g/mol95.5/142.04= 0.6720.672mol/1.15kg= 0.585mol/Kg
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The following data apply to the reaction: A(g) + 3B(g) + 2C(g) → products. Rate[A][B][C]X0.200.400.108X0.400.400.20X0.200.200.204X0.400.400.10 Determine the rate law for the reaction.
Rate law for the reaction is [Products]/[A][B]3[C]2
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A 6.0 grams of NaOH is dissolved in distilled water to make 1.60 - liters of solution. What is the pH of the NaOH solution? AW Na = 23 g/mol ; AW O = 16 g/mol ; AW H = 1 g/mol
pH of the NaOH solution =12.7
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18 g glucose, C6 Hl2O6 (Molar mass = 180 g mol) is dissolved in 1 kg of water in a sauce pan. At
temperature will this solution boil (kb for water = 0.52K kg mol
-1
B.P of pure water = 373.1 K)
Delta;T = mu;*Kb, where mu; is the molality: mu; = n(solute)/m(solvent) n = m/M = 18/180 = 0.1 mol mu; = 0.1/1 = 0.1 mol/kg Delta;T = 0.1*0.52 = 0.052;...
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when 1 mole of barium sulfate was dissolved in water it resulted to a H of 0.52 KJ/mol. How much heat is absorbed when 450g if the compound is dissolved in water has zero effect
Q= m(BaSO4)/Mr(BaSO4)*H=(450/233)*0.52=1 kJAnswer: 1kJ of heat is absorbed
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A solution contains 68.4 g of sucrose (C12H22O11) dissolved in 250 g of water. What is the molality of the solution?
Solution:Molality of a solution is the moles of solute divided by the kilograms of solvent.Molality = Moles of solute (mol) / Mass of solvent (kg)solute = sucrose (C12H22O11) solvent =...
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From an initial mix of: 2 mol Cl2, 1 mol Br2, 0.5 mol I2, 0.5 mol Cl−, 1 mol Br−, 2 mol I−; the total quantity of I2 present after all possible reactions occur is
0.5 mol I2 and 0.5 mol Cl- will not react with anything; 2 mol I- will react with one mol of Cl2 producing one mol of I2: 2I- + Cl2...
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At what temperature will a sucrose solution boil if it contains 1.55 moles of sucrose in 600mL of water? kb of water is 0.51°C/m.
∆T=Kb×m, where m is molality (number of moles of solute per kilogramme of solvent).If the density of water is 1g/ml, 600 ml weights 600 g or 0.6 kg.Molality equals tom=1.55/0.6=2.58(mol/kg)∆T=T-T0,...
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How many molecules of sucrose (C12H22O11, molar mass = 342.30 g/mol) are contained in 14.3 mL of 0.140 M sucrose solution?
140 M = moles / .0143 L.140 * .0143 L = 2.002 moles C12H22)112.002 moles C12H22)11 * 6.022 x 10^23 molecules / 1 mol C12H22 O 11 =1.21 x10^24 molecules...
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