How many molecules of sucrose (C12H22O11, molar mass = 342.30 g/mol) are contained in 14.3 mL of 0.140 M sucrose solution?

Solution:The balanced chemical equation: C12H22O11 + 12O2 --> 12CO2 + 11H2OAccording to the equation: n(C12H22O11) = n(CO2) / 12One mole of any substance contains 6.022×1023 atoms/molecules.Hence,n(C12H22O11) = (2.9×1020 molecules / 6.022×1023 molecules) ×...

Solution:Molality of a solution is the moles of solute divided by the kilograms of solvent.Molality = Moles of solute (mol) / Mass of solvent (kg)solute = sucrose (C12H22O11) solvent =...

Solution:Heptanoic acid = C7H14O2Hydrogen gas = H2C7H14O2 → 7H2According to the scheme above: n(C7H14O2) = n(H2)/7Thus:(8.32 g C7H14O2) × (1 mol C7H14O2 / 130.182 g C7H14O2) × (7 mol H2...

n=m/M A. n = 7.85g / 56g/mol = 0.14 mol B. n = 0.00468g / 28.1 g/mol = 0.00017

0.5 mol I2 and 0.5 mol Cl- will not react with anything; 2 mol I- will react with one mol of Cl2 producing one mol of I2: 2I- + Cl2...

10.013 x 100% / 10.7 = 93.5794393 %

n(C12H22O11) = V*C = 0.050*0.400 = 0.02 molm(C12H22O11) = m*M = 0.02*342 = 6.84 g

The reaction equation is fully balanced.So the quantity of sucrose is equal to the quantity of water - 10 molAnswer: 10 mol

1 mole of glucose was produced by 1 mole of sucrose65 mol of glucose will also be produced by 65 mole of sucrose

108 moles