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If 20.0mL of 0.400M NaCl is added to 80.0mL of 0.900M NaCl. What is the resulting concentration of the NaCl?
Concentration of the NaCl=7.9M
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What Nacl concentration results when 279ml of a 0.730 M NaCl solution is mixed with 467 ml of a 0.400 M NaCl solution
C=0.73+0.4/279+467=0.0015mol/ml
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Calculate the molarity of the NaCl NaCl solution when 14.6 g g of NaCl NaCl is dissolved in 100 mL mL of water.
Molar mass of NaCl= 58.4414.6/58.44=0.25mol0.25/0.1= 2.5mol/L
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The density at 20 0 C of a 0.500 M solution of acetic acid in water is 1.0042 g/mL. What is the molality of the solution? The molar mass of acetic acid, CH3CO2H, is 60.05 g/mol.
Let the volume of the acetic acid solution be 1 litre = 1000 mlthus, moles of acetic acid = molarity*volume of solution in litres = 0.5*1 = 0.5 molesnow, molar...
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Calculate the percent concentration for vinegar made into solution made by dissolving 72.8 mL of acetic acid into 216.4 mL of water
8.7%
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What is the concentration (M) of a NaCl solution prepared by dissolving 5.3 g of NaCl in sufficient water to give 115 mL of solution?
Concentration of NaCl = amountof NaCl / L n of NaCl = 5.3 g/ 58.5 = 0.906 mol (but it is in 115 mL) In one L concentration is 1000/115...
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what is the molal concentration of the solution by dissolving 2.69g of Phenol in 200 g of water
Solution:Cm is the molal concentration expressed in moles of solute dissolved per kilogram of solvent (mol/kg). Cm = (msolute / msolvent) × (1 / MW), where:msolute is the mass of solute in grams...
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A photographic "stop bath" contains 160mL of pure acetic acid. HC2H3O2(1) in 650 mL solution. What is the v/v concentration of acetic acid in the stop bath?
Solution:acetic acid = HC2H3O2 - soluteVolume of acetic acid = 160 mLVolume of the solution = 650 mLv/v concentration = (solute volume / volume of the solution) × 100%v/v(HC2H3O2) =...
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Assuming a density of 5 percent acetic acid by mass solution is 1.0g/mL, determine the volume of the acetic acid solution necessary neutralize 25.0 mL of .10 NaOH.
CH3COOH + NaOH = CH3COONa + H2On=Cm x V = 10 x 0.025= 0.25 moles of NaOHAnd m= n x M = 0.25 x 40 = 10 g, V =...
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A solution of sulfuric acid was made by dissolving 20 grams of 98 percent sulfuric acid in 250 ml of water. Express the concentration of this solution in percent by weight
98% sulphuric acid means in 100 g sulphuric acid source exact amount of sulphuric acid, H2SO4 present 98 g. So in 20 g, exact amount of H2SO4 present =...
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