100ml ,1 M OF sucrose solution when treated with charcol becomes 0.8M .Amount of sucrose adsorbed in moles is ?

С (molality of sucrose) = n (sucrose)/m (water);n (sucrose) = m/M = 67.9/342.2 = 0.2 mole;С (molality of sucrose) = 0.2 mole/94.9 = 0.0021 mole/kg.Answer: C = 0.0021 mole/kg.

Ml of 10% Sucrose solution=83.3 ml

= 0.0035/0.1= 0.035mol/L

Molecular weight of isotonic saline = 58.50.92×58.5 = 53.8253.92/100×100= 53.92%

The concentration of Ca(OH)2 will be equal to concentration of OH- in the solution. pOH of the solution is 14-12 = 2. [OH-] = 10^-2 The number of moles of...

Answer: Factors which influence the adsorption of gases by solids are listed below.Nature of adsorbent: The type of adsorbent also decides the adsorption of the gas. Different molecules interact with...

Number of moles (n) is equal to the mass of the sample (m) divided by the molar mass of the substance (M): n=m / M. Mass of the sample (m)...

Answer: n (O2) = V/Vm n (O2) = 0,1/22,4 = 0,00446 mole

∆T=Kb×m, where m is molality (number of moles of solute per kilogramme of solvent).If the density of water is 1g/ml, 600 ml weights 600 g or 0.6 kg.Molality equals tom=1.55/0.6=2.58(mol/kg)∆T=T-T0,...

BOD = DO0 - DO1= 9-4=5 mg/LAnswer: 5 mg/L