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WHAT IS THE MOLARITY OF A SOLUTION MADE BY DISSOLVING 2.51GRAMS OF SODIUM CARBONATE IN DISTILLED WATER AND MAKING IT UP TO 100ML WITH DISTILLED WATER IN A VOLUMETRIC FLASK
Moles =mass ÷molar massMass =2.51gMolar mass =106Moles = 0.0156875
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Find the molarity of a solution prepared by dissolving 50gram of NaOH in 100ml of water
Molar mass of NaOH=39.997=50/39.997= 1.25moles= 1.25/0.1= 12.5mol/L
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A solution of ethanol is prepared by dissolving 25.0 ml of ethanol in enough water to give a total volume of 250.0 ml. What is the percent-by-volume concentration of ethanol?
percent v/v is (mL ethanol/mL solution)×100.So you have 25.0 mL ethanol/250 mL(25/250)×100 = 10% v/v.
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An isotonic saline solution was prepared by dissolving 0.92 g of NaCI in enough distilled water to make 100 ml solution. What is the percent by mass/volume of the solution?
100-0.92= 99.0899.08/100×100= 99.08%
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how many milliliters of a 10.0% saline solution are needed to make 500 mL of 0.9% saline solution?
Let V ml of a 10.0% saline solution is consider .So , v* 10 / 100 is the mass of solute .------------------- 1 .To Make Solution of 500 mL of...
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A Ni^2+ solution was prepared by dissolving 300.1g of NiCl2.6H2O in 1dm^3 of distilled water. The Ni^2+ concentration of the solution was found to be 1moldm^-3. Calculate the purity of the solution.
The solution is 74.7% pure.
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1. Determine the molarity of a solution containing 10.6g of sodium carbonate dissolve in
a)250cm³ of distilled water
b)500cm³ of distilled water
Solution:Molarity or molar concentration is the number of moles of solute per liter of solution, which can be calculated using the following equation:Molarity = mol solute / L of solution.Molar mass of sodium...
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During the course of an experiment, a student prepared a solution of sodium hydroxide by dissolving 3g of the salt in 100mL of water. Calculate the pH of the solution.
Solution:sodium hydroxide = NaOHThe molar mass of NaOH is 40 g/molHence,(3 g NaOH) × (1 mol NaOH / 40 g NaOH) = 0.075 mol NaOHn(NaOH) = 0.075 molCalculate the molarity...
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What is the molar concentration of normal 0.90% saline (58.44 g/mol) solution? (Assume the density of the normal saline solution is 1.01 g/mL.)
C = n/V n(saline) = m(saline) / M(saline) = 90 g / 58.44 g/mol = 1.54 mol V(solution) = m(solution) / (solution) = 100 g / 1.01 g/mL = 99...
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What is the molarity of a solution made by dissolving 2.00 g of sodium carbonate in distilled water and making it up to 250 mL with distilled water in a volumetric flask?
250 ml=0,25 LC=n/V;n=m/M;n(Na2CO3)=2/106=0,02 molC(Na2CO3)=0,02/0,25=0,08 mol/L
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