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What is the ΔH° for the following reaction (in kJ/mol)? 2 Na <sub>(s) </sub>+ 2 H<sub>2</sub>O<sub> (l)</sub> →<sub> </sub> 2 NaOH<sub> (aq) </sub>+ H<sub>2</sub> <sub>(g)</sub>
From the given info, we know the amount of heat released when 2 moles of Na is reacted. We're asked for the heat per 0.5 moles. So, (368.6 kJ/2mol)0.5000 mol = 92.15...
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N<sub>2(g)</sub>+3H<sub>2(g)</sub>->2NH<sub>3(g)</sub> Given:H<sub>2(g)</sub>=131G N<sub>2(g)</sub>=192 NH<sub>3(g)</sub>0=193. S<sup>0 </sup>values in J/K.mol
Value =199 J/K.mol
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2 Fe<sup>+2</sup>(aq) + H<sub>2</sub>O<sub>2</sub>(aq) ---> 2Fe<sup>+3</sup>(aq) + 2 OH<sup>-1</sup>(aq) What is the oxidation state of oxygen in H<sub>2</sub>O<sub>2</sub>
Oxidation state of oxygen in H2O2.Since hydrogen has an oxidation state of +1Then we'll be having;(1)2+O2=02 + O2 = OThen bringing the constant to the right side have;O2 = -2...
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How many mL of 0.250 M KOH will react with 15.0 mL of 0.350 M H<sub>2</sub>SO<sub>4</sub>? The reaction is : 2KOH + H<sub>2</sub>SO<sub>4</sub> → K<sub>2</sub>SO<sub>4</sub> + 2H<sub>2</sub>O
mL of 0.250 M KOH=5.5
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Derive 𝛂<sub>H3PO4,</sub>𝛂<sub>H2PO4</sub><sup>-</sup>, 𝛂<sub>HPO4</sub><sup>2-</sup>, and 𝛂<sub>PO4</sub><sup>3-</sup> expressions in terms of Ka and hydronium ion concentration.
𝛂H3PO4= 1×10ph= 1×106
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<sup>?</sup><sub>?</sub>? +<sup>14</sup><sub>7</sub>N ⇒ <sup>17</sup><sub>8 </sub>O+ <sup>1</sup><sub>1</sub>H<sub> </sub>
147N+42He→178O+11H714N+24He→817O+11H is an example of a fission reaction
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Electron Pair Geometry of: <ol><li>H<sub>2</sub>Se</li><li>PCl<sub>4</sub><sup>+</sup></li><li>NO<sub>2</sub><sup>-</sup></li><li>BrF<sub>3</sub></li><li>I<sub>3</sub><sup>-</sup></li></ol>
1.Bent with asymmetric charge distribution on the central atom. 2.Tetrahedral3.Trigonal planar
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How many moles of CO<sub>2</sub> will be produced when you burn 12.5 moles of C<sub>2</sub>H<sub>4</sub>? ( C<sub>2</sub>H<sub>4</sub> + 3 O<sub>2</sub> ---> 2 CO<sub>2</sub> + 2 H<sub>2</sub>O )
Mole ratio C2H4:CO2=1:2= 12.5×2=25moles of CO2
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Can you please help me balance this equation?Na[sub]3[/sub]PO[sub]4[/sub] + Ba(NO[sub]3[/sub])[sub]2[/sub] = Ba[sub]3[/sub](PO[sub]4[/sub])[sub]2[/sub] + NaNO[sub]3[/sub]
The correct balanced equation is: Na3PO4 + Ba(NO3)2 = BaPO4 + Na3(NO3)2
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