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Oxidation state of oxygen in H2O2.

Since hydrogen has an oxidation state of +1

Then we'll be having;

(1)2+O2=0

2 + O2 = O

Then bringing the constant to the right side have;

O2 = -2 Dividing both side by 2, we have;

O = -1

Therefore the oxidation state of Oxidation state of oxygen in H2O2 is -1

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