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Which of these atoms has the largest number of neutrons in the nucleus? (a) <sup>148</sup>Eu (b) <sup>157</sup>Dy (c) <sup>149</sup>Nd (d) <sup>162</sup>Ho (e) <sup>159</sup>Gd
d,e
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1. Calculate the pH of the solution with (H<sup>+</sup>)= 1.0 x 10<sup>-3</sup> 2. Calculate the pH of the solution with (H<sup>+</sup>)= 3.6 x 10<sup>-5</sup>
pH= -log[H+]pH= -log[1×10^-3]pH= 32) pH= -log[3.6×10^-5]pH= 5-log3.6pH= 4.44
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If AgCN is added to water it found however, that 1 liter of solution contains x mole of AgCN, the solubility product is a) 4x<sup>3 </sup>b) x<sup>2</sup> c) x<sup>4</sup> d) 27x<sup>5</sup>
a) 4x3
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2 Fe<sup>+2</sup>(aq) + H<sub>2</sub>O<sub>2</sub>(aq) ---> 2Fe<sup>+3</sup>(aq) + 2 OH<sup>-1</sup>(aq) What is the oxidation state of oxygen in H<sub>2</sub>O<sub>2</sub>
Oxidation state of oxygen in H2O2.Since hydrogen has an oxidation state of +1Then we'll be having;(1)2+O2=02 + O2 = OThen bringing the constant to the right side have;O2 = -2...
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Derive 𝛂<sub>H3PO4,</sub>𝛂<sub>H2PO4</sub><sup>-</sup>, 𝛂<sub>HPO4</sub><sup>2-</sup>, and 𝛂<sub>PO4</sub><sup>3-</sup> expressions in terms of Ka and hydronium ion concentration.
𝛂H3PO4= 1×10ph= 1×106
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<sup>?</sup><sub>?</sub>? +<sup>14</sup><sub>7</sub>N ⇒ <sup>17</sup><sub>8 </sub>O+ <sup>1</sup><sub>1</sub>H<sub> </sub>
147N+42He→178O+11H714N+24He→817O+11H is an example of a fission reaction
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Electron Pair Geometry of: <ol><li>H<sub>2</sub>Se</li><li>PCl<sub>4</sub><sup>+</sup></li><li>NO<sub>2</sub><sup>-</sup></li><li>BrF<sub>3</sub></li><li>I<sub>3</sub><sup>-</sup></li></ol>
1.Bent with asymmetric charge distribution on the central atom. 2.Tetrahedral3.Trigonal planar
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Identify the 4 quantum numbers from the given electronic configurations a. 3p<sup>3</sup> b. 5p<sup>5</sup> c. 4s<sup>2</sup> d. 3p<sup>1</sup>
Energy (n), angular momentum (ℓ), magnetic moment (mℓ), and spin (ms).
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ClO<sub>3</sub> <sup>-</sup> (aq) + I<sup>-</sup> (aq) I<sub>2</sub> (s) + Cl<sup>-</sup> (aq) [acidic]
In acidic medium,ClO3- + 6H+ +6e Cl- + 3H2O ……..(iii)2I- - 2e I2 (iv)Multiplying eqn. iii with 1 and eqn iv with 3 and then adding we getClO3- + 6H+ + 6I- 3I2 + Cl- + 3H2O
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A container of 10 litres has a volume expressed in m<sup>3</sup> A. 1m<sup>3</sup> B. 0.01m<sup>3</sup> C. 0.001m<sup>3</sup> D. 0.0001m<sup>3</sup>
1 cubic metre =1000 litres10l = 1×10/1000 = 0.01B. 0.01m3
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