Electron Pair Geometry of: <ol><li>H<sub>2</sub>Se</li><li>PCl<sub>4</sub><sup>+</sup></li><li>NO<sub>2</sub><sup>-</sup></li><li>BrF<sub>3</sub></li><li>I<sub>3</sub><sup>-</sup></li></ol>

Md Ariful Islam

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Md Ariful Islam

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1.Bent with asymmetric charge distribution on the central atom.

2.Tetrahedral

3.Trigonal planar

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Which of these atoms has the largest number of neutrons in the nucleus? (a) <sup>148</sup>Eu (b) <sup>157</sup>Dy (c) <sup>149</sup>Nd (d) <sup>162</sup>Ho (e) <sup>159</sup>Gd

d,e

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Balance the following equation by the electron-balancing method. Name oxidizing and reducing agents: NH<sub>3 </sub>+ O<sub>2</sub><sup> </sup>= N<sub>2</sub><sup> </sup>+ H<sub>2</sub>O

4NH3 + 3O2    = 2N2 + 6H2O4 N-III - 12 e- → 4 N0 (oxidation)6 O0 + 12 e- → 6 O-II (reduction)

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N<sub>2(g)</sub>+3H<sub>2(g)</sub>-&gt;2NH<sub>3(g)</sub> Given:H<sub>2(g)</sub>=131G N<sub>2(g)</sub>=192 NH<sub>3(g)</sub>0=193. S<sup>0 </sup>values in J/K.mol

Value =199 J/K.mol

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2 Fe<sup>+2</sup>(aq) + H<sub>2</sub>O<sub>2</sub>(aq) ---&gt; 2Fe<sup>+3</sup>(aq) + 2 OH<sup>-1</sup>(aq) What is the oxidation state of oxygen in H<sub>2</sub>O<sub>2</sub>

Oxidation state of oxygen in H2O2.Since hydrogen has an oxidation state of +1Then we'll be having;(1)2+O2=02 + O2 = OThen bringing the constant to the right side have;O2 = -2...

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Derive 𝛂<sub>H3PO4,</sub>𝛂<sub>H2PO4</sub><sup>-</sup>, 𝛂<sub>HPO4</sub><sup>2-</sup>, and 𝛂<sub>PO4</sub><sup>3-</sup> expressions in terms of Ka and hydronium ion concentration.

𝛂H3PO4= 1×10ph= 1×106

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<sup>?</sup><sub>?</sub>? +<sup>14</sup><sub>7</sub>N ⇒ <sup>17</sup><sub>8 </sub>O+ <sup>1</sup><sub>1</sub>H<sub> </sub>

147N+42He→178O+11H714N+24He→817O+11H is an example of a fission reaction

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How many moles of CO<sub>2</sub> will be produced when you burn 12.5 moles of C<sub>2</sub>H<sub>4</sub>? ( C<sub>2</sub>H<sub>4</sub> + 3 O<sub>2</sub> ---&gt; 2 CO<sub>2</sub> + 2 H<sub>2</sub>O )

Mole ratio C2H4:CO2=1:2= 12.5×2=25moles of CO2

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Can you please help me balance this equation?Na[sub]3[/sub]PO[sub]4[/sub] + Ba(NO[sub]3[/sub])[sub]2[/sub] = Ba[sub]3[/sub](PO[sub]4[/sub])[sub]2[/sub] + NaNO[sub]3[/sub]

The correct balanced equation is: Na3PO4 + Ba(NO3)2 = BaPO4 + Na3(NO3)2

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Iron oxide formula Fe<sub>2</sub>O<sub>3 </sub>how many molecules of Fe<sub>3</sub>O<sub>3 </sub>there in (5x<sup>2</sup>) mol of Fe<sub>2</sub>O<sub>3</sub>, if x=4?

3.21 * 1025 molecules

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A container of 10 litres has a volume expressed in m<sup>3</sup> A. 1m<sup>3</sup> B. 0.01m<sup>3</sup> C. 0.001m<sup>3</sup> D. 0.0001m<sup>3</sup>

1 cubic metre =1000 litres10l = 1×10/1000 = 0.01B. 0.01m3

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