1. Calculate the pH of the solution with (H⁺)= 1.0 x 10^-3 2. Calculate the pH of the solution with (H⁺)= 3.6 x 10^-5

1 yd2 = 8.361×10-25 Tm24.14×1025 yd2 = 4.4×1025 × 8.361×10-25 Tm2= 36.7884 Tm2

d,e

H= mcΔtm= H/cΔt= 42000/(4.2×100) = 100g

a) 4x3

v=m/Mv(HCl)=5mol5mol=m/36.6g/molm=183gv(HCl)2=12+2=14molm(HCl)=14mol*36.6g/mol=512.4gw=183g/512.4g*100%=35.71%

Kb-the degree of dissociation of the solution into ionsRight variant: 4

DHo = -844 kJ; DSo = -165 kJ/K

147N+42He→178O+11H714N+24He→817O+11H is an example of a fission reaction

Energy (n), angular momentum (ℓ), magnetic moment (mℓ), and spin (ms).

1 cubic metre =1000 litres10l = 1×10/1000 = 0.01B. 0.01m3