how to prepare a 5moldm<sup>-3</sup> HCl solution from 12moldm<sup>-3 </sup>and 2moldm<sup>-3 </sup>HCl solution

Md Ariful Islam

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Md Ariful Islam

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v=m/M

v(HCl)=5mol

5mol=m/36.6g/mol

m=183g

v(HCl)2=12+2=14mol

m(HCl)=14mol*36.6g/mol=512.4g

w=183g/512.4g*100%=35.71%

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