If you keep pressure constant, the gas is expanding from 0.120 L to 0.610 Liters. Take the change in Volumes and multiply it by pressure to get the work done.
In this case, the piston is doing work on the environment so it would lose E, and thus your answer should be a negative number.
Old $"Dalton's Law of Partial Pressures"$ states that in a gaseous mixture, the exerted by a component gas is the same as it would have exerted if it alone occupied...
1 Answers 1 viewsThis is an example of a problem. $color(blue)(bar(ul(|color(white)(a/a)(p_1V_1)/T_1 = (p_2V_2)/T_2color(white)(a/a)|)))" "$ We can rearrange this formula to get $V_2 = V_1 × p_1/p_2 ×...
1 Answers 1 viewsAt constant $T$, $P_1V_1=P_2V_2$....... We solve for $P_2=(P_1V_1)/V_2$, and clearly the $"RHS"$ will have the required units of pressure: $P_2=(1.5*atmxx5.6*L)/(4.8*L)=1.75*atm$ That $P_2>P_1$ is quite reasonable, because we are compressing the...
1 Answers 1 viewsFrom the $PV=nRT$ we can conclude that $n=(PV)/(RT)$. If the pressure $P$, the volume $V$ and the temperature $T$ of the gas change between two points, this change can be...
1 Answers 1 viewsThis is asking you to apply the definition of reversible work: $w_"rev" = -P int_(V_1)^(V_2) dV$ $= -P (V_2 - V_1) = -"288 J"$ Since the gas did...
1 Answers 1 viewsRaising the temperature will increase the volume: $V_T=(300K)/(200K)xx24.0L=36.0L$ Increasing the pressure will decrease the volume: $V_(T,p)=(10.0atm)/(14.0atm)xx36.0L~~25.7L$ It doesn't matter if you first do the one and then the other, or...
1 Answers 1 viewsAnd so.................. $V_2=(P_1xxV_1xxT_2)/(T_1xxP_2)$ $=(2.31*atmxx17.5*Lxx350*K)/(299*Kxx1.75*atm)<=30*L.$
1 Answers 1 viewsUsing $PV=nRT$ and knowing that $nRT$ stays constant you should get: $P_1V_1=P_2V_2$ or $6.414*850=V_2*4423$ and $V_2=1.232 liters$
1 Answers 1 viewsBoyles Law is the only inverse relationship between gas phase variable of the Empirical Gas Law set. That is ... For the Empirical the primary variables considered are Pressure...
1 Answers 1 viewsAnd $"(ii) the LATENT heat of fusion of ice...."$ And $"(iii) the heat capacity of liquid water...."$ And $"(iv) the heat of vaporization of water...."$ And $"(v) the heat capacity...
1 Answers 1 views