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A piston has an external pressure of 5.00 atm. How much work has been done in joules if the cylinder goes from a volume of 0.120 liters to 0.610 liters?
If you keep pressure constant, the gas is expanding from 0.120 L to 0.610 Liters. Take the change in Volumes and multiply it by pressure to get the work done....
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Five gases combined in a gas cylinder have the following partial pressures 3.00 atm ($N_2$), 1.80 atm ($O_2), 0.29 atm (Ar), 0.18 atm (He), and 0.10 atm (H). What is the total pressure that is exerted by the gases?
Old $"Dalton's Law of Partial Pressures"$ states that in a gaseous mixture, the exerted by a component gas is the same as it would have exerted if it alone occupied...
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A gas occupies 3.30 liters and is at 850 mmHg. What would the pressure be in atm, if the new volume were increased to 5.63 liters?
This is a clear application of $"Boyle's Law"$ $Pprop1/V$ And thus, $P_1V_1=P_2V_2$ We note that $1*atm-=760*mm*Hg$ $P_2=(P_1V_1)/V_2$ $=$ $((850*mm*Hg)/(760*mm*Hg*atm^-1))xx(3.30*L)/(5.63*L)$ $=$ $??atm$ This is not a good question. It has...
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Synthetic diamonds can be manufactured at pressures of $6.00 times 10^4$ atm. If we took 2.00 liters of gas at 1.00 atm and compressed it to a pressure $6.00 times 10^4$
atm, what would the volume of that gas be?
Apply $"Pressure "xx" Volume "=" Constant"$ The temperature being constant $P_1V_1=P_2V_2$ The initial volume is $V_1=2L$ The initial pressure $P_1=1atm$ The final pressure is $P_2=6*10^4atm$ The final volume is...
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A gas takes up a volume of 19.5 liters, has a pressure of 2.9 atm, and a temperature of 5.5°C. If I raise the temperature to 65°C and lower the pressure to 1.5 atm, what is the new volume of the gas?
From the $PV=nRT$ we can conclude that $n=(PV)/(RT)$. If the pressure $P$, the volume $V$ and the temperature $T$ of the gas change between two points, this change can be...
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If I initially have a gas at a pressure of 10.0 atm, a volume of 24.0 liters, and a temperature of 200. K, and then I raise the pressure to 14.0 atm and increase the temperature to 300. K, what is the new volume of the gas?
Raising the temperature will increase the volume: $V_T=(300K)/(200K)xx24.0L=36.0L$ Increasing the pressure will decrease the volume: $V_(T,p)=(10.0atm)/(14.0atm)xx36.0L~~25.7L$ It doesn't matter if you first do the one and then the other, or...
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A gas takes up a volume of 17.5 liters, has a pressure of 2.31 atm, and a temperature of 299 K. lf the temperature is increased to 350 K and the pressure is decreased to 1.75 atm, what is the new volume of the gas?
And so.................. $V_2=(P_1xxV_1xxT_2)/(T_1xxP_2)$ $=(2.31*atmxx17.5*Lxx350*K)/(299*Kxx1.75*atm)<=30*L.$
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A sample of gas in a cylindrical chamber with a removable piston occupied a volume of 6.414 liters when the pressure was 850 torr and the temperature was 27.2 degree C. The Pressure was just readjusted to 4423 torr by moving the piston. ?
Using $PV=nRT$ and knowing that $nRT$ stays constant you should get: $P_1V_1=P_2V_2$ or $6.414*850=V_2*4423$ and $V_2=1.232 liters$
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At a pressure 47 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 8 liters, what is the new pressure?
Boyles Law is the only inverse relationship between gas phase variable of the Empirical Gas Law set. That is ... For the Empirical the primary variables considered are Pressure...
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If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then l raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
This is an example of a problem. $color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2|)$ We can rearrange this formula to get $V_2 = V_1 × P_1/P_2 × T_2/T_1$...
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