This is a clear application of $"Boyle's Law"$ $Pprop1/V$ And thus, $P_1V_1=P_2V_2$ We note that $1*atm-=760*mm*Hg$ $P_2=(P_1V_1)/V_2$ $=$ $((850*mm*Hg)/(760*mm*Hg*atm^-1))xx(3.30*L)/(5.63*L)$ $=$ $??atm$ This is not a good question. It has...
1 Answers 1 viewsGiven $Pprop1/V$, $P_1V_1=P_2V_2$, and the great advantage of this proportionality is that we can use unorthodox units of pressure and volume, i.e. $"psi, pints, atmosphere, gallons"$ so long as we...
1 Answers 1 views$V_2-=(P_1V_1)/P_2=((380*mm*Hg)/(760*mm*Hg*atm^-1)xx6.0*L)/((760*mm*Hg)/(760*mm*Hg*atm^-1)$ $=$ $??L$
1 Answers 1 viewsFrom the $PV=nRT$ we can conclude that $n=(PV)/(RT)$. If the pressure $P$, the volume $V$ and the temperature $T$ of the gas change between two points, this change can be...
1 Answers 1 viewsRaising the temperature will increase the volume: $V_T=(300K)/(200K)xx24.0L=36.0L$ Increasing the pressure will decrease the volume: $V_(T,p)=(10.0atm)/(14.0atm)xx36.0L~~25.7L$ It doesn't matter if you first do the one and then the other, or...
1 Answers 1 viewsBoyles Law is the only inverse relationship between gas phase variable of the Empirical Gas Law set. That is ... For the Empirical the primary variables considered are Pressure...
1 Answers 1 viewsWhen you are given this much information in the context of a generic, unnamed gas, it's a good idea to consider the : $PV = nRT$ Before we...
1 Answers 1 viewsEven without doing any calculations, you should be able to look at the information given and predict that the volume of the gas will increase after temperature is increased and...
1 Answers 1 viewsThis is an example of a problem. $color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2|)$ We can rearrange this formula to get $V_2 = V_1 × P_1/P_2 × T_2/T_1$...
1 Answers 1 viewsThis is an example of the . The equation to use is: $(P_1V_1)/T_1=(P_2V_2)/(T_2)$, where $P$ is the pressure, $V$ is the volume, and $T$ is the temperature in...
1 Answers 1 views