A gas takes up a volume of 19.5 liters, has a pressure of 2.9 atm, and a temperature of 5.5°C. If I raise the temperature to 65°C and lower the pressure to 1.5 atm, what is the new volume of the gas?

Md Ariful Islam

0 like 0 dislike
1 views
Share with your friends

1 Answers

Md Ariful Islam

Call

From the $PV=nRT$ we can conclude that $n=(PV)/(RT)$.

If the pressure $P$, the volume $V$ and the temperature $T$ of the gas change between two points, this change can be illustrated by:

$n=(P_1V_1)/(RT_1)=(P_2V_2)/(RT_2)$

Therefore, this expression can be modified as:

$(P_1V_1)/(cancel(R)T_1)=(P_2V_2)/(cancel(R)T_2)=>(P_1V_1)/(T_1)=(P_2V_2)/(T_2)$

Thus, $V_2=(P_1V_1)/(T_1)xx(T_2)/(P_2)$

$V_2=(2.9cancel(atm)xx19.5L)/(278.5cancel(K))xx(338cancel(K))/(1.5cancel(atm))=45.8L$

0 like 0 dislike
1 views
Talk Doctor Online in Bissoy App
A sample of a gas has a volume of of 2.0 liters at a pressure of 1.0 atmosphere. When the volume increases to 40 liters, at constant temperature, what will the pressure be?

This is an example of which states that the volume of a gas varies inversely with pressure, when mass and temperature are kept constant. Equation $V_1P_1=V_2P_2$, where $V$ is volume...

1 Answers 1 views
A gas occupies 3.30 liters and is at 850 mmHg. What would the pressure be in atm, if the new volume were increased to 5.63 liters?

This is a clear application of $"Boyle's Law"$ $Pprop1/V$ And thus, $P_1V_1=P_2V_2$ We note that $1*atm-=760*mm*Hg$ $P_2=(P_1V_1)/V_2$ $=$ $((850*mm*Hg)/(760*mm*Hg*atm^-1))xx(3.30*L)/(5.63*L)$ $=$ $??atm$ This is not a good question. It has...

1 Answers 1 views
Initially a gas is at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K, and then the pressure is raised to 14 atm and the temperature to 300 K. What is the new volume of the gas?

$V_2$ $=$ $(P_1V_1T_2)/(P_2T_1)$ $(12*atmxx23*Lxx300K)/(14*atmxx200*K)$ $=$ $??L$ The volume has increased reasonably in that the temperature has increased substantially, yet the pressure has only increased marginally.

1 Answers 1 views
A gas has a volume of 6.0 liters at a pressure of 380 mm Hg. The pressure is increased to gas 760 mm Hg at the same temperature. What is its new volume?

$V_2-=(P_1V_1)/P_2=((380*mm*Hg)/(760*mm*Hg*atm^-1)xx6.0*L)/((760*mm*Hg)/(760*mm*Hg*atm^-1)$ $=$ $??L$

1 Answers 1 views
Synthetic diamonds can be manufactured at pressures of $6.00 times 10^4$ atm. If we took 2.00 liters of gas at 1.00 atm and compressed it to a pressure $6.00 times 10^4$ atm, what would the volume of that gas be?

Apply $"Pressure "xx" Volume "=" Constant"$ The temperature being constant $P_1V_1=P_2V_2$ The initial volume is $V_1=2L$ The initial pressure $P_1=1atm$ The final pressure is $P_2=6*10^4atm$ The final volume is...

1 Answers 1 views
If I initially have a gas at a pressure of 10.0 atm, a volume of 24.0 liters, and a temperature of 200. K, and then I raise the pressure to 14.0 atm and increase the temperature to 300. K, what is the new volume of the gas?

Raising the temperature will increase the volume: $V_T=(300K)/(200K)xx24.0L=36.0L$ Increasing the pressure will decrease the volume: $V_(T,p)=(10.0atm)/(14.0atm)xx36.0L~~25.7L$ It doesn't matter if you first do the one and then the other, or...

1 Answers 1 views
A gas takes up a volume of 17.5 liters, has a pressure of 2.31 atm, and a temperature of 299 K. lf the temperature is increased to 350 K and the pressure is decreased to 1.75 atm, what is the new volume of the gas?

And so.................. $V_2=(P_1xxV_1xxT_2)/(T_1xxP_2)$ $=(2.31*atmxx17.5*Lxx350*K)/(299*Kxx1.75*atm)<=30*L.$

1 Answers 1 views
At a pressure 47 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 8 liters, what is the new pressure?

Boyles Law is the only inverse relationship between gas phase variable of the Empirical Gas Law set. That is ... For the Empirical the primary variables considered are Pressure...

1 Answers 1 views
Fifty liters of gas is kept at a temperature of 200 K and under pressure of 15 atm. The temperature of the gas is increased to 400 K. The pressure is decreased to 7.5 atm. What is the resulting volume of the gas?

Even without doing any calculations, you should be able to look at the information given and predict that the volume of the gas will increase after temperature is increased and...

1 Answers 1 views
If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then l raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?

This is an example of a problem. $color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2|)$ We can rearrange this formula to get $V_2 = V_1 × P_1/P_2 × T_2/T_1$...

1 Answers 1 views
X