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Raising the temperature will increase the volume:
Increasing the pressure will decrease the volume:
It doesn't matter if you first do the one and then the other, or the other way around, or both simultaneously
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A gas occupies 3.30 liters and is at 850 mmHg. What would the pressure be in atm, if the new volume were increased to 5.63 liters?
This is a clear application of $"Boyle's Law"$ $Pprop1/V$ And thus, $P_1V_1=P_2V_2$ We note that $1*atm-=760*mm*Hg$ $P_2=(P_1V_1)/V_2$ $=$ $((850*mm*Hg)/(760*mm*Hg*atm^-1))xx(3.30*L)/(5.63*L)$ $=$ $??atm$ This is not a good question. It has...
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Initially a gas is at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K, and then the pressure is raised to 14 atm and the temperature to 300 K. What is the new volume of the gas?
$V_2$ $=$ $(P_1V_1T_2)/(P_2T_1)$ $(12*atmxx23*Lxx300K)/(14*atmxx200*K)$ $=$ $??L$ The volume has increased reasonably in that the temperature has increased substantially, yet the pressure has only increased marginally.
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A gas takes up a volume of 19.5 liters, has a pressure of 2.9 atm, and a temperature of 5.5°C. If I raise the temperature to 65°C and lower the pressure to 1.5 atm, what is the new volume of the gas?
From the $PV=nRT$ we can conclude that $n=(PV)/(RT)$. If the pressure $P$, the volume $V$ and the temperature $T$ of the gas change between two points, this change can be...
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At constant pressure, what temperature must be reached to increase a 100-milliliter sample of a gas initially at 300 K to a volume of 200 milliliters?
Given The volume $V_1$ of a gas at a temperature $T_1$. A second volume $V_2$. Find The second temperature $T_2$. Strategy A problem involving two gas volumes and two...
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A gas takes up a volume of 17.5 liters, has a pressure of 2.31 atm, and a temperature of 299 K. lf the temperature is increased to 350 K and the pressure is decreased to 1.75 atm, what is the new volume of the gas?
And so.................. $V_2=(P_1xxV_1xxT_2)/(T_1xxP_2)$ $=(2.31*atmxx17.5*Lxx350*K)/(299*Kxx1.75*atm)<=30*L.$
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500.0 liters of a gas are prepared at 700.0 mmHg and 200.0 C. The gas is placed into a tank under high pressure. When the tank cools to 20.0 C, the pressure of the gas is 30.0 atm. What is the volume of the gas?
And thus $760*mm*Hg-=1*atm$ The combined gas equation tells us that $(P_1V_1)/T_1=(P_2V_2)/T_2$ given a constant molar quantity of gas. So we solve for $V_2$, where $V_2$ is conceived to be the...
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Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). At 200°C in a closed container, 1.05 atm of nitrogen gas is mixed with 2.02 atm of hydrogen gas. At equilibrium the total pressure is 2.02 atm. What is the partial pressure of hydrogen gas at equilibrium?
First, write the balanced chemical equation for the equilibrium and set up an ICE table. $color(white)(XXXXXX)"N"_2 color(white)(X)+color(white)(X)"3H"_2 color(white)(l)⇌ color(white)(l)"2NH"_3$ $"I/atm": color(white)(Xll)1.05 color(white)(XXXl)2.02 color(white)(XXXll)0$ $"C/atm": color(white)(X)-x color(white)(XXX)-3x color(white)(XX)+2x$ $"E/atm": color(white)(l)1.05- x...
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At a pressure 47 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 8 liters, what is the new pressure?
Boyles Law is the only inverse relationship between gas phase variable of the Empirical Gas Law set. That is ... For the Empirical the primary variables considered are Pressure...
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Fifty liters of gas is kept at a temperature of 200 K and under pressure of 15 atm. The temperature of the gas is increased to 400 K. The pressure is decreased to 7.5 atm. What is the resulting volume of the gas?
Even without doing any calculations, you should be able to look at the information given and predict that the volume of the gas will increase after temperature is increased and...
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If I initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a temperature of 200 K, and then l raise the pressure to 14 atm and increase the temperature to 300 K, what is the new volume of the gas?
This is an example of a problem. $color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2|)$ We can rearrange this formula to get $V_2 = V_1 × P_1/P_2 × T_2/T_1$...
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