A sample of a gas has a volume of of 2.0 liters at a pressure of 1.0 atmosphere. When the volume increases to 40 liters, at constant temperature, what will the pressure be?

Md Ariful Islam

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This is an example of which states that the volume of a gas varies inversely with pressure, when mass and temperature are kept constant.

Equation
$V_1P_1=V_2P_2$, where $V$ is volume and $P$ is pressure.

Known
$V_1="2.0 L"$
$P_1="1.0 atm"$
$V_2="40 L"$

Unknown
$P_2$

Solution
Rearrange the equation to isolate $P_2$. Substitute the known values into the equation and solve.

$P_2=(V_1P_1)/V_2$

$P_2=((2.0cancel"L")xx(1.0"atm"))/(40cancel"L")="0.05 atm"$

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