How many helium atoms are in a helium blimp containing 494 kg of helium?

Md Ariful Islam

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Step 1: calculate how the number of moles using the molar mass.
The molar mass of helium = $4.00$ g/mol.
This means that 1 mole of helium atoms weighs 4 gram.

In this case you have $494$ kg which is $494.000$ grams. How many moles is this?

$(494.000 color(red)cancel(color(black)(gram)))/ (4.00 color(red)cancel(color(black)(gram))/(mol)) = 123.500 mol$

Step 2 : calculate the number of atoms using Avogadro's constant.
Avogadro's constant states that there are $6.02*10^23$ atoms in one mole of any element.

How many atoms are in 123.500 moles?

$6.02*10^23 "atoms"/color(red)cancel(color(black)((mol))) * 123.500 color(red)cancel(color(black)(mol)) = 7.44*10^28 "atoms"$

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