How many helium atoms are there in a helium blimp containing 535 kg of helium?

The molar mass of helium is $4.00*g$. $"Moles of substance"$ $=$ $"Mass of substance"/"Molar mass of substance"$ $(38.00*cancelg)/(4.00*cancelg*mol^-1)$ $=$ $??mol$

$rho,"density"="Mass"/"Volume"$ And thus $"Mass"$ $=rhoxx"volume"$ And here, $"Mass"$ $=$ $0.1765*kg*m^-3xx2000*m^3$ $=353*kg$

Phosphorus is an element. Elements are usually converted from moles to atoms using Alvogardo's number $ 6.02 xx 10^23$ If phosphorus is in elemental form it is not necessary to...

A single $""^12C$ atom contains 6 nuclear protons, and 6 neutrons, and to a first approx. this represents the mass of the atom. Five $""^12C$ atoms should thus have a...

$"Calcium cyanide"$ is formulated by taking the calcium ion, $Ca^(2+)$, and binding it to 2 equiv of the cyanide ion, $""^(-):C-=N$. So for $7xxCa$, $10xxC$, and $9xxN$, at most...

Your strategy here will be to use the Planck - Einstein relation to calculate the energy of a single photon of wavelength $"535 nm"$, then use the total energy of...

Note: This answer may seem to be quite long, but that is because I have tried to explain each of the steps fully and clearly. If you want, you can...

$N_A$ is simply another collective number like a dozen, or a gross, or a score. Admittedly, $N_A$ is a VERY large number. We have $2.12xxN_A$ molecules of propane, $H_3C-CH_2-CH_3$. If...

Step 1: calculate how the number of moles using the molar mass. The molar mass of helium = $4.00$ g/mol. This means that 1 mole of helium atoms weighs...

is just another number, admittedly it is a very large number, $N_A=6.022xx10^23*mol^-1$. Let's do the problem by using $"dozens"$: $"1 dozen"="12 items of stuff"$. $a.$ $"6 dozen S atoms"$...