is just another number, admittedly it is a very large number, $N_A=6.022xx10^23*mol^-1$. Let's do the problem by using $"dozens"$: $"1 dozen"="12 items of stuff"$.
$a.$ $"6 dozen S atoms"$ $-=$ $"72 sulfur atoms"$
$b.$ $"2 dozen"$ $S_8$ $"atoms"$ $-=$ $"192 sulfur atoms"$
$c.$ $"5 dozen"$ $SO_2$ $"molecules"$ $-=$ $"60 sulfur atoms"$ and $"120 oxygen atoms"$.
$d.$ $"2 dozen"$ $CO_2$ $"molecules"$ $-=$ $"24 carbon atoms"$ and $"48 oxygen atoms"$.
And the answer is clearly $b.$ Are you following me?