According to your question you need a kind of energy density in $"Joules"/m^3$. Observing the units of your data you have: Power divided by area or $"Watts"/m^2="Joule"/(s*m^2)$ By dividing it...
1 Answers 1 viewsThis can be a difficult concept for some, but most of space contains no matter whatsoever–it's just emptiness. Dark Matter, a little understood thing that seems to have gravity but...
1 Answers 1 viewsThe product moles per liter created in sixty seconds are sixty times the moles per liter created in just one second, provided the rate is constant. That is because there...
1 Answers 1 viewsStep 1. Convert milligrams to kilograms. $"19 000" color(red)(cancel(color(black)("mg"))) × (1 color(red)(cancel(color(black)("g"))))/(1000 color(red)(cancel(color(black)("mg")))) × "1 kg"/(1000 color(red)(cancel(color(black)("g")))) = "0.019 kg"$ Step 2. Convert litres to cubic metres. $1 color(red)(cancel(color(black)("L")))...
1 Answers 1 viewsWe work out (i) the molar quantity of helium gas.... $"Moles of helium"=(535*kgxx10^3*g*kg^-1)/(4.0*g*mol^-1)=133750*mol.$ And then (ii) we mulitply this molar quantity by Avogadro's number....$N_A=6.022xx10^23*mol^-1$ to get the number of helium...
1 Answers 1 views$rho=19.5*g*cm^3=(19.5*10^-3*kg)/(10^-2m)^3$ $(19.5xx10^-3*kg)/(10^-6m^3)$ $(19.5xx10^-3*kgxx10^6)m^-3$ because $(1/x^-1=1/(1/x)=x)$ $=19.5xx10^3*kg*m^-3$ The price of gold is currently $$1232-10*USD*"troy ounce"^-1$. Given that a $"troy ounce"$ $-=$ $31.1*g$, how much is your nugget worth?
1 Answers 1 views$"Density"$ $=$ $"mass"/"volume"$ $=$ $(8*g)/(2*cm^3)$ $=$ $4*g*cm^-3$ When we put the units into these sorts of calculations, it is an extra check on our accuracy. We try to calculate a...
1 Answers 1 viewsHere, $rho=(37.4*g)/(2.2xx10^3*L)$ $=$ $??g*L^-1$. Doing the calculation like this gives an answer in $g*L^-1$ as required for a .
1 Answers 1 viewsFrequency is the number of complete cycles per second. So $160000000$ vibrations per second is equivalent to a frequency of $f=160MHz$. So half this frequency would be $80MHz$. Since radio...
1 Answers 1 viewsStep 1: calculate how the number of moles using the molar mass. The molar mass of helium = $4.00$ g/mol. This means that 1 mole of helium atoms weighs...
1 Answers 1 views