Amaterial weighs 8 grams and takes up 2 cubic centimeters of space. What is the material's density in grams per cubic centimeter ($g/(cm^3)$)?

This can be a difficult concept for some, but most of space contains no matter whatsoever–it's just emptiness. Dark Matter, a little understood thing that seems to have gravity but...

= mass $xx$ volume So you are multiplying two numbers. When multiplying, the number of is determined by the number with the least number of significant digits. The volume...

Since aluminum has a of $2.7 g//(cm)^3$, $1275g$ of aluminum has a volume of $472.2 cm^3$. This is calculated by the formula linking density to mass and volume, $density =...

$"1 fluid oz=29.5735 mL"$ $"1 mL=1cm"^3"$ To convert fluid ounces (fl oz) to cubic centimeters $("cm"^3")$, multiply fl oz times $29.5735"mL/fl oz"$. $12cancel"fl oz"xx(29.5735"mL")/(1cancel"fl oz")="354.882 mL"$ Since $"1 mL=1 cm"^3"$,...

$"Density"$ $ (rho)$ $=$ $("mass")/("volume")$ $rho$ $=$ $(1.96xx10^3*g)/(3400*cm^3)$ $=$ $??$. Note, $1$ $kg$ $=$ $10^3*g$

By definition, is the mass per unit volume. $therefore rho=m/V$ $=(33.6g)/(14cm^3)$ $=2.4g//cm^3$ $=2400kg//m^3$

$rho$ $=$ $(32.0*g)/((16.8-12.3)*mL)$ Note that $1*mL=1*cm^-3$.

$"Density, "rho$ $-=$ $"Unit mass"/"Unit Volume"$ Here, both mass and volume were quoted, and we simply take the quotient, knowing that $1*L$ $=$ $1000*cm^3$. Thus $"rho$ $-=$ $(3.15xx10^3g)/(2.50*cancelLxx10^3*cm^3*cancel(L^-1))$ $=$ $??g*cm^-3$

$rho="Mass"/"Volume"=(16*g)/(8*cm^-3)$ $=$ $??*g*cm^-3$ And the volume of each piece is $??*cm^3$.

$rho, "density"="mass"/"volume"=(21.6*g)/(8.0*cm^3)=??*g*cm^-3$. And I all have done is simply taken the appropriate quotient. Would this float on water? What is the in $g*mL^-1$?