Which option contains a $2g$ mass of sodium atoms.... $1.$ $5.24xx10^22"sodium atoms?"$ $2.$ $6.022xx10^24"sodium atoms?"$ $3.$ $3.12xx10^23"sodium atoms?"$ $4.$ $5.24xx10^22*"sodium atoms?"$

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Md Ariful Islam · Answer 1 · Apr 02, 2024 09:48:30

We know that $1*mol$ contains $6.022xx10^23$ individual sodium atoms, and has a mass of $22.99*g$.

And thus for $1.$ there is a $2*g$ mass of $Na$.

For $2.$ there is a $22.99*g$ mass of $Na$.

For $3.$ there is a ..............................

$(3xx10^23*"sodium atoms")/(6.022xx10^23*"sodium atoms"*mol^-1)xx22.99*g*mol^-1$ mass of $Na$, approx. $11.5*g$.

For $4.$ there is a $8*g$ mass of sodium............

And so, clearly,..................Capisce?

Which option contains a $2*g$ mass of sodium atoms.... $1.$ $5.24xx10^22*"sodium atoms?"$ $2.$ $6.022xx10^24*"sodium atoms?"$ $3.$ $3.12xx10^23*"sodium atoms?"$ $4.$ $5.24xx10^22*"sodium atoms?"$