The weighted average is the sum of each individual nuclide, multiplied by its isotopic abundance. So, we simply do the arithmetic: $0.7577xx34.969+0.2423xx36.966 = ???$ amu Then look at to...
1 Answers 1 viewsThe bond energy, or bond , expresses the energy needed to break a chemical bond, that's why it will always be listed as a positive value. In your case, 243...
1 Answers 1 views2Fe + 3Cl2 -> 2FeCl3
1 Answers 1 viewsYou have to search the between Na and $Cl_2$ You have $ n= "mass"/"molecular mass" = (103,0 g)/(23,0 (g/(mol))) = 4,47 mol $ of Na. As 1 mole occupies 22,4...
1 Answers 1 viewsWe know that $1*mol$ contains $6.022xx10^23$ individual sodium atoms, and has a mass of $22.99*g$. And thus for $1.$ there is a $2*g$ mass of $Na$. For $2.$ there is...
1 Answers 1 viewsThe idea here is that you need to use the of the two in the two to find their . Once you have their , you also have the ratio...
1 Answers 1 viewsRemember that is a NUMERICAL (or extensive) quantity. I could say just as correctly that 2 dozen sodium atoms react with 1 dozen chlorine molecules to form 2 dozen sodium...
1 Answers 1 viewsThe equation above is certainly balanced. I don't know whether it is valid or not, inasmuch as I have never seen this reaction done. Given the balanced equation 3 equiv...
1 Answers 1 viewsIncreasing the concentration of $Cl_2$ will increase the concentration of the products on the right side of the equilibrium equation. To decrease the concentration of the products the equilibrium will...
1 Answers 1 viewsWell, I would never recommend this "trial-and-error" method... I don't see why you should ever "have" to do it... just use the quadratic formula on the resulting quadratic equation. I...
1 Answers 1 views