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A chemist obtains 2.50 moles of sodium nitrate ($NaNO_3$). What is the mass of this sample?

Md Ariful Islam

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Md Ariful Islam

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You are given $"2.50 moles"$ of sodium nitrate, $(NaNO3)$.

Given moles, now, you are to convert back to mass (in grams).

To do this, you need to set up the problem as follows:

First, find the formula mass of the compound using the periodic table.

$Na = 23 g$
$N = 14 g$
$O = 16g * 3 = 48 g$

Total = 85 grams

So, for every $1 "mole"$ of $NaNO_3$, you have 85 grams.

We will set up a conversion factor to solve for mass in grams of the sample using moles of $NaNO_3$.

$(2.50 cancel"moles")/1 * (85color(white)(.)"grams")/(1 cancel"mole") = "212.5 grams"$

Answer: 212.5 grams of $NaNO_3$

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