Sodium phosphate =
Calcium nitrate =
Sodium nitrate =
Calcium phosphate =
$Na_"3"PO_"4" (aq) + Ca(NO_"3")_"2" (aq) -> NaNO_"3" (aq) + Ca_"3"(PO_"4")_"2" (s)$
States might be wrong :/
... but hope this helps :)
$"Moles of calcium"$ $=$ $(1200xx10^-3*g)/(40.08*g*mol^-1)$ $=$ $0.04008*mol$. And thus we need $0.04008*mol$ $"calcium carbonate"$, i.e. a mass of $0.04008*molxx100.09*g*mol^-1$ $=$ $??g$.
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1 Answers 1 views