1 Answers
Call
Talk Doctor Online in Bissoy App
An average sample of chlorine contains 75.77% chlorine-35, with an atomic mass of 34.969 amu (atomic mass units), and 24.23% chlorine-37, with an atomic mass of 36.966 amu. What is the average atomic mass of chlorine?
The weighted average is the sum of each individual nuclide, multiplied by its isotopic abundance. So, we simply do the arithmetic: $0.7577xx34.969+0.2423xx36.966 = ???$ amu Then look at to...
1 Answers 1 views
Arsenic reacts with chlorine to form a chloride. If 1.587 g of arsenic reacts with 3.755 g of chlorine what is the empirical formula of the chloride?
$"Moles of arsenic"$ $=$ $(1.587*g)/(74.92*g*mol^-1)=0.0212*mol$. $"Moles of chlorine"$ $=$ $(3.755*g)/(35.45*g*mol^-1)=0.106*mol$. We divide thru by the lowest molar quantity to give $AsCl_5$. This is not chemical you would find in a...
1 Answers 1 views
Zinc oxide reacts with hydrochloric acid to produce zinc chloride and dihydrogen monoxide. If 3.6 moles of zinc oxide reacts with an excess of hydrochloric acid, then how many grams of zinc chloride were produced?
The reaction happening in solution is the following: $ZnO(aq)+2HCl(aq)->ZnCl_2(aq)+H_2O(l)$ Since the hydrochloric acid ($HCl$) is in excess, therefore, the number of moles of Zinc oxide ($ZnO$) will determine the mass...
1 Answers 1 views
How many molecules of chlorine gas would be produced if 10.0g of aluminum chloride decomposed into aluminum precipitate and chlorine gas?
First you need to write the correct BALANCED chemical reaction equation. Then you can determine how many moles of $Cl_2$ would be produced from the available moles of Cl in...
1 Answers 1 views
A chemist performs the synthesis of sodium chloride from its elements. The chemist begins with 46 grams of sodium. How many moles of chlorine are needed?
2 Na + Cl2 → 2 NaCl
$"Moles of sodium "=(46.0*g)/(22.9*g*mol^-1)=2*mol$. Given your equation, clearly we need the ONE mole of $Cl_2$ gas. What is the mass of this quantity of chlorine? It is fact that all...
1 Answers 1 views
Sodium and chlorine gas react to produce sodium chloride. If $"234 g"$ of sodium chloride is produced, how much sodium reacted?
You know that $2"Na"_ ((s)) + "Cl"_ (2(g)) -> 2"NaCl"_ ((s))$ and that the reaction produced $"234 g"$ of sodium chloride. Convert this to moles by using the...
1 Answers 1 views
35.0 grams of thionyl chloride is placed in a glass containing 500.0 grams of water. After the reaction is complete how many grams of water will remain unreacted? How many grams of the thionyl chloride will remain unreacted?
Thionyl chloride reacts quantitatively (and violently) with water as represented by the following reaction: $SOCl_2(l) + 2H_2O(l) rarr SO_2(g)uarr + 2HCl(aq)+Delta$ $"Moles of thionyl chloride"=(35.0*g)/(118.97*g*mol^-1)=0.294*mol.$ And CLEARLY, thionyl chloride is...
1 Answers 1 views
Sodium and chlorine react to form sodium chloride: 2Na (s) + Cl2 (g) ----> 2NaCl (s)
For the reaction of 44.0g Na with 69.9 g Cl2, what is the limiting reactant and what is the theoretical yield of sodium chloride in grams?
This is a limiting reactant problem. We know that we will need a balanced equation with masses, molar masses, and moles of the involved. 1. Gather all the information...
1 Answers 1 views
When ethane, $C_2H_6$, reacts with chlorine gas the main product is $C_2H_5Cl$ but small amounts of $C_2H_4Cl_2$ are produced. What is the percent yield of $C_2H_5Cl$ if the reaction of 125g of ethane with 255g of chlorine gas produced 206g of $C2H_5Cl$?
The key here is to focus solely on the reaction that produces chloroethane, $"C"_2"H"_5"Cl"$, and ignore the one that produces dichloroethane, $"C"_2"H"_4"Cl"$, the side product of the reaction. Start by...
1 Answers 1 views
At 273.15 K and 100kPa, 58.34 g of $"HCl"$ reacts with 0.35 mol of $"MnO"_2$ to produce $"7.056 dm"^3$ of chlorine gas. Calculate the theoretical yield of chlorine. How do I solve this?
Start by taking a look at the balanced chemical equation for this $"MnO"_ (2(s)) + color(red)(4)"HCl"_ ((aq)) -> "MnCl"_ (2(aq)) + "Cl"_ (2(g)) uarr + 2"H"_ 2"O"_((l))$...
1 Answers 1 views