How to write and balance the equation for the reaction: sodium fluoride plus copper(II) nitrate produces sodium nitrate plus copper(II) fluoride?

Md Ariful Islam

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Md Ariful Islam

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You need to determine the formulas first.

sodium fluoride: $"NaF"$

copper(II) nitrate: $"Cu(NO"_3)"_2$

sodium nitrate: $"NaNO"_3$

copper(II) fluoride: $"CuF"_2$

$"NaF + Cu(NO"_3)_2"$$rarr$$"NaNO"_3 + "CuF"_2$

All of these are ionic. If we look first at the polyatomic ion $"NO"_3"^-$ as a whole, we can see that there are two of them on the lefthand side and one on the righthand side. So you need to place a coefficient of $2$ in front of $"NaNO"_3"$. That will cause the $"NaF"$ to be unbalanced, so you need to place a coefficient of $2$ in front of $"NaF"$. This will balance the fluoride ions, and you're done.

$"2NaF + Cu(NO"_3)_2"$$rarr$$"2NaNO"_3 + "CuF"_2$

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